From mboxrd@z Thu Jan  1 00:00:00 1970
From: Jeff Sickel <jas@corpus-callosum.com>
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Date: Tue, 10 Aug 2010 00:23:44 -0500
Message-Id: <09DB2D65-A18A-493E-9886-2D5D3334F460@corpus-callosum.com>
To: Fans of the OS Plan 9 from Bell Labs <9fans@9fans.net>
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Subject: [9fans] regexp metacharacter difficulty inside grap
Topicbox-Message-UUID: 46479bde-ead6-11e9-9d60-3106f5b1d025

I've been trying to figure out this little one for a while now and =
figure I could use a refresher course in regexp.

There are quite a few files that I'm trying to copy through grap that =
would be really easy if I could take a line like:

	# (Yo 4.9534)

and turn it into a value for x,y graphing.  Unfortunately, I'm =
completely blanking out on how to get that pesky ')' stripped out.  I =
try the following:

	if "$2" =3D=3D "(Yo" then {
	 	print sprintf("Yo was %f", yo)
		 yo =3D sh { echo $3 | sed 's/\)#//' }
		 print sprintf("Yo is %f", yo)
	}=20

but that just gives me:

	cpu% eval `{doctype t.g} | lp -dstdout > t.ps
		Yo was 8.579000
	rc: line 2: token ')': syntax error
	grap: syntax error???: No such file or directory
	 near 20100809_pscheck_XX.d:8
	 context is
		yo =3D sh { echo 4.9534)# | sed 's/\)#//' } >>> <<<


I'm not quite sure why grap converts $3 into "4.9534)#", so I try brute =
force:

	cpu% echo '4.9534)#' | sed 's/\)#//'=20
	4.9534


Does anyone have any hints on what might I be doing wrong in my grap =
source?

-jas