From mboxrd@z Thu Jan  1 00:00:00 1970
From: Dan Cross <cross@math.psu.edu>
Message-Id: <200107061441.KAA25020@augusta.math.psu.edu>
To: 9fans@cse.psu.edu
Subject: Re: [9fans] thread
In-Reply-To: <20010706042502.AE409199D7@mail.cse.psu.edu>
Cc:
Date: Fri,  6 Jul 2001 10:41:11 -0400
Topicbox-Message-UUID: c34bbfb4-eac9-11e9-9e20-41e7f4b1d025

In article <20010706042502.AE409199D7@mail.cse.psu.edu> you write:
>Thank you, Dan,

Thanks, Kenji, though I think that Dennis' note was better.  :-)

#include <u.h>
>#include <libc.h>
>main(){
>	int a[1];
>	a[0] = 10;
>	print("%d\n",*a);
>	print("%d\n",a);
>	print("%d\n",&a);
>	print("%d\n",*&a);
>	print("%d\n",*(&a));

These are the two that confused me, since they output:

>2147479448
>2147479448

However, Dennis clarified how it worked when he pointed out the
type differences between a and &a (the former is int *, the latter
int (*)[1]).  I believe that in the case of *&a, you end up with
a variable of type a[1], which decays into int *.  Restated another
way, it's as if the * and & cancel each other out, leaving you
an unadorned a, which turns into int *.

At least, I believe that's how it works; I'd love to be corrected
if I'm wrong.  Since this isn't comp.lang.c, I can actually look
forward to such a thing.  ;-p

	- Dan C.