From mboxrd@z Thu Jan  1 00:00:00 1970
Date: Thu, 22 Apr 2010 23:26:09 +0200
From: tlaronde@polynum.com
To: Fans of the OS Plan 9 from Bell Labs <9fans@9fans.net>
Message-ID: <20100422212609.GA2513@polynum.com>
References: <20100422175033.GA6247@polynum.com>
	<87d97130a41364706523e641fe0dd372@plan9.bell-labs.com>
	<20100422193236.GA2388@polynum.com>
	<20100422200740.49F7D5B73@mail.bitblocks.com>
	<20100422211551.GA987@polynum.com>
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Subject: Re: [9fans] BUG!!! in Plan9 compiler!
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On Thu, Apr 22, 2010 at 11:15:51PM +0200, tlaronde@polynum.com wrote:
>
> I get:
>
> gcc: -201
> ken-cc: 2147483447 (2^31 - 201)
>
> This is: signed long + signed long + unsigned char.
>
> Do you mean that there is first promotion :
>
> 	1) unsigned char is promoted to unsigned int (A6.1).
>
> 	2) And since there is an arithmetic operator (/ or shift),
> 	unsigned int value may exceeds signed long == signed int, the
> 	signed long is converted to unsigned long (A6.2)?
>
> Is it this?!!!!?
>
> And when I do first assignment, there is only promotion (since no
> operator is here). Yielding the correct value in x2, that is then
> divided (or shifted) by 2, hence signed, and no problem?

I say non-sense: even in the assignment, there is still arithmetic
conversions: the '+'...

I don't get it...
--
        Thierry Laronde <tlaronde +AT+ polynum +dot+ com>
                      http://www.kergis.com/
Key fingerprint = 0FF7 E906 FBAF FE95 FD89  250D 52B1 AE95 6006 F40C