From mboxrd@z Thu Jan  1 00:00:00 1970
Message-ID: <87a5a6791443529cf29a59a55e5d7186@quanstro.net>
From: erik quanstrom <quanstro@quanstro.net>
Date: Thu, 22 Jan 2009 18:01:37 -0500
To: 9fans@9fans.net
In-Reply-To: <dd6fe68a0901221454r2e9299edk31968f870640eb35@mail.gmail.com>
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Subject: Re: [9fans] fun question
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On Thu Jan 22 17:55:55 EST 2009, rsc@swtch.com wrote:
> >> <- is a unary operator.
>
> > okay, what does it do? (unless you meant -> in C++)
>
> it receives from a channel.

i assumed that ron was talking about c.
in c, "<- 0" tokenizes as "<", "-", and "0".
"-" is taken to be a unary operator on "0".

even gcc does this correctly:

; cat > x.c
#include <u.h>
#include <libc.h>

void
x(int seed)
{
	int m_31;

	m_31 = 1<<31;
	if(seed <- 0)
		seed = seed + m_31;
	print("seed %d\n", seed);
}

void
main(void)
{
	x(-5);
	exits("");
}
<eot>; 9c x.c
; 9l x.o
; ./a.out
seed -2147483648

- erik