From mboxrd@z Thu Jan  1 00:00:00 1970
Message-ID: <9ab217670603012052t733f79f8m@mail.gmail.com>
Date: Wed,  1 Mar 2006 20:52:43 -0800
From: "Devon H. O'Dell" <devon.odell@gmail.com>
To: "Fans of the OS Plan 9 from Bell Labs" <9fans@cse.psu.edu>
Subject: Re: [9fans] A Plan 9 C request....
In-Reply-To: <4405FD26.6080607@lanl.gov>
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	<4405FD26.6080607@lanl.gov>
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2006/3/1, Ronald G Minnich <rminnich@lanl.gov>:
> Brantley Coile wrote:
> >>now means
> >>
> >>      { int i; for(i=3D0; i<10; i++); }
> >
> >
> > Does that mean the following will compile?
> >
> > void
> > f(void)
> > {
> >       i =3D 3;
> >       put(i);
> >       for (int i =3D 0; i < 3; i++)
> >               put(i);
> >       if (i =3D=3D 4) put(4);
> > }
> >
>
>   cat > t.c
> void
> f(void)
> {
>          i =3D 3;
>          put(i);
>          for (int i =3D 0; i < 3; i++)
>                  put(i);
>          if (i =3D=3D 4) put(4);
> }
> [rminnich@q tmp]$ cc t.c
> t.c: In function 'f':
> t.c:4: error: 'i' undeclared (first use in this function)
> t.c:4: error: (Each undeclared identifier is reported only once
> t.c:4: error: for each function it appears in.)
> t.c:6: error: 'for' loop initial declaration used outside C99 mode
> [rminnich@q tmp]$
>
>
> ron

And the reason it doesn't is because in this code snippet, the
variable i is undeclared. I assume since the i is not declared, the
compiler steps out of C99 mode and refuses to allow the C99 construct
of for (int i...)

--Devon