Re: [9fans] regexp metacharacter difficulty inside grap

["Federico G. Benavento" <benavento@gmail.com>]

this is probably related to the fact that grap(1) is an APE program,
and sh actually execs sh, not rc...

On Tue, Aug 10, 2010 at 2:23 AM, Jeff Sickel <jas@corpus-callosum.com> wrote:
> I've been trying to figure out this little one for a while now and figure I could use a refresher course in regexp.
>
> There are quite a few files that I'm trying to copy through grap that would be really easy if I could take a line like:
>
>        # (Yo 4.9534)
>
> and turn it into a value for x,y graphing.  Unfortunately, I'm completely blanking out on how to get that pesky ')' stripped out.  I try the following:
>
>        if "$2" == "(Yo" then {
>                print sprintf("Yo was %f", yo)
>                 yo = sh { echo $3 | sed 's/\)#//' }
>                 print sprintf("Yo is %f", yo)
>        }
>
> but that just gives me:
>
>        cpu% eval `{doctype t.g} | lp -dstdout > t.ps
>                Yo was 8.579000
>        rc: line 2: token ')': syntax error
>        grap: syntax error???: No such file or directory
>         near 20100809_pscheck_XX.d:8
>         context is
>                yo = sh { echo 4.9534)# | sed 's/\)#//' } >>> <<<
>
>
> I'm not quite sure why grap converts $3 into "4.9534)#", so I try brute force:
>
>        cpu% echo '4.9534)#' | sed 's/\)#//'
>        4.9534
>
>
> Does anyone have any hints on what might I be doing wrong in my grap source?
>
> -jas
>
>
>



-- 
Federico G. Benavento