From mboxrd@z Thu Jan  1 00:00:00 1970
MIME-Version: 1.0
In-Reply-To: <20140902200400.81EAAB827@mail.bitblocks.com>
References: <346c54679a6cdc9bb557724d8b93bbc6@quintile.net>
	<6e2a7a02201fcf3ea5d0d894d0d16916@ladd.quanstro.net>
	<20140902200400.81EAAB827@mail.bitblocks.com>
Date: Tue,  2 Sep 2014 14:10:57 -0700
Message-ID: <CAJSxfm+vDRwVqZGxJK1rDvJnj7AF0VJSW80yMCFxCe2awF8F+w@mail.gmail.com>
From: Skip Tavakkolian <skip.tavakkolian@gmail.com>
To: Fans of the OS Plan 9 from Bell Labs <9fans@9fans.net>
Content-Type: text/plain; charset=UTF-8
Subject: Re: [9fans] silly question
Topicbox-Message-UUID: 14d40922-ead9-11e9-9d60-3106f5b1d025

inspired me to write discotime:

% cat discotime.go
// print the number of seconds from the dawn of Disco until the date
in the argument
package main

import (
    "fmt"
    "os"
    "time"
)

func main() {
    for _, s := range os.Args[1:] {
        d, err := time.Parse(time.UnixDate, s)
        if err != nil {
            panic(err)
        }
        fmt.Println(d.Unix())
    }
}
% ./discotime 'Tue Aug 16 17:03:52 CDT 1977'
240599032

to make a hammertime (http://en.wikipedia.org/wiki/U_Can't_Touch_This)
you can subtract 1990 from parsed date instead.

-Skip


On Tue, Sep 2, 2014 at 1:04 PM, Bakul Shah <bakul@bitblocks.com> wrote:
> On Tue, 02 Sep 2014 15:10:56 EDT erik quanstrom <quanstro@quanstro.net> wrote:
>> > Strftime is a red herring (sorry), I can use  and "date" | getline
>> > to generate pretty much any date string I need.
>> >
>> > The issue is more going the other way. tm2sec in awk is quite complex
>> > and hids many pitfalls if you want to do it correctly.
>> >
>> > My problem is parsing logfiles which contain dates in the form
>> > of date(1) / ctime(2).
>> >
>> > I want to graph stuff over time and so I want a monotonically incrementing
>> > number (secs sinc 1/1/70 would be ideal). I have coded this in awk but
>> > for one year leap years break - though not by much.
>>
>> if the hair is just leap years, the algorithm used by /sys/src/libc/9sys/ctim
>> e.c
>> is pretty attractive.  the idea is to just loop through the years between giv
>> en
>> and 1970, and add a day for each leap year encountered.  should be easy
>> to do in awk.
>
> plan9 doesn't deal with leap seconds, right?  There've been 35
> leap seconds since 1972 (International Atomic Time is 35
> seconds ahead of GMT).  Though this probably doesn't matter
> for timestamps in log files.
>