Re: [9fans] void*

[Charles Forsyth <charles.forsyth@gmail.com>]

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it's void* because that can be assigned between other pointer types without
a cast.
x = malloc(sizeof(*x)); instead of x = (T*)malloc(sizeof(*x)); which just
adds clutter.
Similarly it's just free(x) instead of free((void*)x); (or free((uchar*)x)
as I understand your suggestion).


On Sun, 15 May 2022 at 11:59, adr <adr@sdf.org> wrote:

> Hi,
> one of the first thing I noticed compiling in plan9 is that arithmetic
> on void* is illegal. Other compilers treat void* as uchar*.
> Conceptually, it  makes sense. A pointer to void doesn't point to
> any object. But then I've seen the use of void* in functions (like
> memccpy) when the pointed object is going to be processed as a
> byte array. Local uchar*'s are used to do the trick inside the
> function.
> 
> It wouldn't make more sense to avoid the use of void*
> and just use instead uchar* or better still u8int*?
> 
> Some thoughts?
> 
> Regards,
> adr.

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