From: erik quanstrom <quanstro@quanstro.net>
To: 9fans@9fans.net
Subject: Re: [9fans] Recursive structural expressions?
Date: Thu, 20 Aug 2009 21:01:33 -0400 [thread overview]
Message-ID: <a85dde21bb450f779bc73f5c904cfa55@quanstro.net> (raw)
In-Reply-To: <3aaafc130908201721g78bb3613y9d081aca10fa7d9d@mail.gmail.com>
> Here's an example. Let's make the syntax extra pukey: @#, where # is
> 1-9, defines a `named procedure', which is the same thing as putting
> something in braces in Sam.
>
> x/.*\n/ @1{ ( @1 ) | @1 ( @1 ) ( ) | }
>
x/re/ repeatedly sets . with matches until the input
is exhausted. so i don't think i understand your example.
how does /.*\n/{(.*\n)|.*\n(.*\n)|} match anything
but the tautological .*\n|? for example, if the input
is "line1\nline2\n", then . is in turn "line1\n" and "line2\n",
and both match .*\n|.
where do the actions go in your example?
- erik
next prev parent reply other threads:[~2009-08-21 1:01 UTC|newest]
Thread overview: 15+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-08-20 17:52 J.R. Mauro
2009-08-20 19:53 ` erik quanstrom
2009-08-20 20:33 ` J.R. Mauro
2009-08-20 20:39 ` erik quanstrom
2009-08-20 21:14 ` J.R. Mauro
2009-08-20 21:26 ` erik quanstrom
2009-08-21 0:21 ` J.R. Mauro
2009-08-21 1:01 ` erik quanstrom [this message]
2009-08-21 1:14 ` Charles Forsyth
2009-08-22 1:10 ` J.R. Mauro
2009-08-23 19:59 ` Aharon Robbins
2009-08-23 21:27 ` Rob Pike
2009-08-21 13:58 ` J. R. Mauro
2009-08-21 14:24 ` Russ Cox
2009-08-21 14:57 ` J. R. Mauro
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