[9fans] e0|e01 on regexp(3)

[trebol@india.com]

Using a little script I wrote to rename files, I encounter a funny
behavior with '|'.  If the regular expressions share a part, doesn't
matter the order of those,  The first match from the start of the input
is processed.  Now that I'm writing this, it's seems obviously the
right behavior (and I think it is), for example:


	% echo '123' | sed s'/12|12/o/g'
	o3
	% echo '123' | sed s'/23|12/o/g'
	o3

But in large concatenations with strange characters like in:
	$ echo '__-' | sed s'/_-|_-_|-_|__+ ... and a lot of more cra* ... /__/g'

You could expect the output be '__', but it's '__-'

So... if you are a retard like me, don't try to be such smart and use
various sed commands.

trebol.