From mboxrd@z Thu Jan  1 00:00:00 1970
Message-ID: <e08c1c96b2d7585872f3bef99a353606@quanstro.net>
From: erik quanstrom <quanstro@quanstro.net>
Date: Sat, 15 Jul 2006 06:22:52 -0500
To: 9fans@cse.psu.edu
Subject: Re: [9fans] An acid-question
In-Reply-To: <466b269ce739adc433673872f2a17422@mail.gmx.net>
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i doesn't exist -- it was optimized away because your code is equivalent to this

void
m00(...)
{
	int i;

	if(foo){
		for(i = 0; i <= n; i++){
			some_data[i] = srcdata[i]
		}

	} else {
		...
	}
}

because i == j.

- erik

On Sat Jul 15 05:55:56 CDT 2006, sretzki@gmx.de wrote:
>
> Hi folks,
>
> I got a function which goes like this:
> void
> m00(...)
> {
> 	int i,j = 0;
>
> 	if(foo) {
>
> 		for(i=0;i<=n;i++) {
> 			some_data[j++] = srcdata[i]
> 		}
>
> 	} else {
> 		...
> 	}
> }
>
> (ignore the errors)
>
> I get a fault write. Jippie. Starting to acid arround, I came across this:
>
> acid: *m00:j
> 0x00000000
> acid: *m00:i
> <stdin>:3: (error) colon: local variable not found
> acid:
>
> so obviously acid does not 'see' i because it is first used in a new block (the if()), at least I guess so. How do I display the value of i in acid?
>
>
> Mfg, Sascha