From mboxrd@z Thu Jan  1 00:00:00 1970
Message-ID: <edf1ac0aa3b09970139ff9b1b67d2dc4@quanstro.net>
From: erik quanstrom <quanstro@quanstro.net>
Date: Sat, 15 Jul 2006 07:39:27 -0500
To: 9fans@cse.psu.edu
Subject: Re: [9fans] An acid-question
In-Reply-To: <f922c3ebb9b910062887c323645bbc40@mail.gmx.net>
MIME-Version: 1.0
Content-Type: text/plain; charset="US-ASCII"
Content-Transfer-Encoding: 7bit
Topicbox-Message-UUID: 80c545e0-ead1-11e9-9d60-3106f5b1d025

On Sat Jul 15 07:37:29 CDT 2006, sretzki@gmx.de wrote:
> > your loop test has an obiwan error:
> >
> > 		for(i=0;i <= inbyterate;i++) {
> >
> > should be
> > 		for(i = 0; i < inbyterate; i++);
> >
>
> heh.. 'oups' ;) .. Thanks Erik. Nevertheless, that is not the problem. Do you have an idea why acid does not 'see' i ? Or how I can investigate i?

i = j/2.  i'm still pretty sure that kenc is optimizing i away.  here's what i'd
do.  if samplerate is large (~10000), you need to make sure that data and datacopy
are not on the stack.  then run acid on the broken process and make sure you're
actually on the line expected and use i = j/2 to figure out what i is.

- erik