From mboxrd@z Thu Jan  1 00:00:00 1970
MIME-Version: 1.0
In-Reply-To: <22fc94a82c16f8b347bc45dd539b5fc6@coraid.com>
References: <fb731e27c1f324c07e285a5b6f8b674e@ladd.quanstro.net>
	<d50d7d460911300710u697638cxf890f10283ee3a44@mail.gmail.com>
	<71b1e3b728efbd1b2a2ae2b5b4e2b1d0@coraid.com>
	<3aaafc130911300754i7f244f02j7d161d907d7a8bed@mail.gmail.com>
	<22fc94a82c16f8b347bc45dd539b5fc6@coraid.com>
Date: Mon, 30 Nov 2009 19:38:07 +0100
Message-ID: <f4d8fa40911301038x3bc6e8adx3d1ac8d1b766d534@mail.gmail.com>
From: hiro <23hiro@googlemail.com>
To: Fans of the OS Plan 9 from Bell Labs <9fans@9fans.net>
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: quoted-printable
Subject: Re: [9fans] =?utf-8?q?gr=C3=ABp_=28rhymes_with_creep=29_and_cptmp?=
Topicbox-Message-UUID: a5876fb2-ead5-11e9-9d60-3106f5b1d025

>> iff e unfolds to the same set as =C3=AB. If e only unfolds to [e], then
>> [e-f] would unfold to [ef].
>
> i don't think that works. =C2=A0consider [e-g]. =C2=A0normally
> this would match 'f', but under your algorithm it wouldn't.

I don't get it, why not? Especially, what algorithm are we speaking about?