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Subject: Re: [9front] 9pc64
From: Kenji Arisawa <arisawa@ar.aichi-u.ac.jp>
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memory command on 9pc64 

term% memory
total          15.9 GB
total kernel   2 GB
total user     13.9 GB

used  user     8.32 MB
used  kernel   11.6 MB
used  draw     13.3 MB
term% 



Test if large memory is really allocated to a process.

H2: Test Code

void
main(int argc, char *argv[])
{
	char *p, buf[256];
	ulong i,n[4];
	ulong GB = 1024*1024*1024;

	ARGBEGIN{
	default: usage();
	}ARGEND

	n[0] = 1;
	n[1] = 1;
	n[2] = 1;
	n[3] = 1;

	for(i = 0; i< 4; i++){
		p = malloc(n[i]*GB);
		print("%d %dGB %08p\n",i,n[i],p);
	}
	read(0,buf, sizeof(buf));
}


H2: The Result

H3:	9front (9pc64)

term% 6.out
0 1GB 00401938
1 1GB 404019a0
2 1GB 80401a08
3 1GB 00000000

the 6.out is running
term% ps | grep 6.out
arisawa        1383    0:00   0:00       56K Pread    6.out
term% memory
total          15.9 GB
total kernel   2 GB
total user     13.9 GB

used  user     8.28 MB
used  kernel   10.5 MB
used  draw     13.3 MB
term% 

H3:	9front (9pcf)

term% 8.out
0 1GB 0000a4a0
1 1GB 00000000
2 1GB 00000000
3 1GB 00000000

the 8.out is running
term% ps |grep 8.out
arisawa        1843    0:00   0:00       48K Pread    8.out
term% memory
total          3.42 GB
total kernel   154 MB
total user     3.27 GB

used  user     859 MB
used  kernel   6.38 MB
used  draw     8.77 MB
term% 

Totally OK.
It would be better if we get total memory size allocated to a process.
memory command on both 9pcf and 9pc64 does not show malloced size.

On 2014/05/02, at 6:51, cinap_lenrek@felloff.net wrote:

> so it works?
> 
> --
> cinap