Hi, In the following scenario, I would like to remove the first rule of expr. But I can't find the good arguments for the command DELETE_RULE. $ rlwrap ocaml -I +camlp4 -I +ulex # #load "camlp4rf.cma" ;; # #load "pa_ulex.cma" ; # open Camlp4.PreCast ; # Gram.Entry.print Format.std_formatter Syntax.expr ; # DELETE_RULE Gram Syntax.expr: "lexer"; OPT "|"; LIST0 [ regexp; "->"; expr ] SEP "|" END ; Unbound value regexp Otherwise, is there a way to know if the active syntax, is the revised or not? Thank you. -- Serge Leblanc gpg --keyserver hkp://keyserver.ubuntu.com:11371 --recv-keys 0x33243C1B Fingerprint = 066C 005F 5595 D85C 7673 D969 1DD4 90C4 3324 3C1B