Re: nth_root of num?

[Claude Marche <Claude.Marche@lri.fr>]

>>>>> "Namhyun Hur" == N Hur <mapnh@maths.bath.ac.uk> writes:

    Namhyun Hur> Hi,

    Namhyun Hur> I am wondering if anyone has a function "nth_root"
    Namhyun Hur> for big_int in camllight. As far as I know only
    Namhyun Hur> "sqrt_big_int" is provided in the num library. Could
    Namhyun Hur> anyone send me the code if it is possible?

    Namhyun Hur> Regards,

    Namhyun Hur> 	Namhyun Hur.

I have written one, here is the code. It works with a personal version
of power, where the second argument is an int, not a num.

There is one function that rounds the result to the floor, one to the
ceiling. Of course, it is working only on big_ints, not ratios. 

Hope this helps, (Any comments welcome)

-- 
| Claude Marché           | mailto:Claude.Marche@lri.fr |
| LRI - Bât. 490          | http://www.lri.fr/~marche/  |
| Université de Paris-Sud | phoneto: +33 1 69 15 64 85  |
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open Num;;

let num_one = Int 1;;

let rec power_num x = function
    0 -> num_one
  | 1 -> x
  | n ->
      let y = square_num (power_num x (n/2))
      in
      	if (n mod 2)=0
      	then y
	else mult_num y x
;;

let root_floor n x =

  if le_num x num_one
  then x
  else
    let predn = pred n
    in
    let numpredn = Int predn
    and numn = Int n
    in
    let rec approx y =
      let ypnm1 = (power_num y predn)
      in      
      let new_y = 
      	quo_num 
      	  (add_num (mult_num numpredn (mult_num y ypnm1)) x) 
	  (mult_num numn ypnm1)
      in
      	if ge_num new_y y
      	then y
      	else approx new_y
    in 
      approx x
;;

let root_ceil n x =
  succ_num (root_floor n (pred_num x))
;;