From: John Whitley <whitley@cse.buffalo.edu>
To: caml-list@inria.fr
Subject: Re: nth_root of num?
Date: Tue, 1 Dec 1998 15:25:26 -0500 (EST) [thread overview]
Message-ID: <13924.20450.862916.697199@hadar.cs.Buffalo.EDU> (raw)
In-Reply-To: <13923.50811.334235.394872@sun8f.LRI>
Claude Marche writes:
> An algorithm for computing the nth root of a float is easy :
>
> let nth_root n x = exp (log(x)/.(float_of_int n));;
Alternatively, one could use the (**) float exponentiation operator:
let nth_root n x = x ** (1.0 /. n);;
-- John
prev parent reply other threads:[~1998-12-02 12:48 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
1998-11-25 13:48 N Hur
1998-11-26 16:23 ` Claude Marche
[not found] ` <Pine.SOL.4.05.9812011025090.6015-100000@odin.maths.bath.ac.uk>
1998-12-01 10:35 ` Claude Marche
1998-12-01 20:25 ` John Whitley [this message]
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