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From: John Whitley <whitley@cse.buffalo.edu>
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Date: Tue,  1 Dec 1998 15:25:26 -0500 (EST)
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Subject: Re: nth_root of num?
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Claude Marche writes:
 > An algorithm for computing the nth root of a float is easy :
 > 
 > let nth_root n x = exp (log(x)/.(float_of_int n));;

Alternatively, one could use the (**) float exponentiation operator:

let nth_root n x = x ** (1.0 /. n);;

-- John