* [Caml-list] selecting GADT parameter
@ 2015-07-31 13:48 Ashish Agarwal
2015-07-31 13:57 ` Carl Eastlund
2015-08-04 9:21 ` Goswin von Brederlow
0 siblings, 2 replies; 7+ messages in thread
From: Ashish Agarwal @ 2015-07-31 13:48 UTC (permalink / raw)
To: Caml List
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I have:
type _ t =
| Foo1 : 'a * int -> int t
| Foo2 : 'a * string -> 'a t
but I really want to merge these two cases. I want the return type to be
based on the second arg when the second arg is int, and be based on the
first arg otherwise. Any way to accomplish that?
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* Re: [Caml-list] selecting GADT parameter
2015-07-31 13:48 [Caml-list] selecting GADT parameter Ashish Agarwal
@ 2015-07-31 13:57 ` Carl Eastlund
2015-07-31 14:18 ` Ashish Agarwal
2015-08-04 9:21 ` Goswin von Brederlow
1 sibling, 1 reply; 7+ messages in thread
From: Carl Eastlund @ 2015-07-31 13:57 UTC (permalink / raw)
To: Ashish Agarwal; +Cc: Caml List
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Perhaps like this? (Caveat: I typed this straight into gmail, I haven't
tried to compile or run this code at all.)
type ('a, 'b, 'c) tag =
| Tag1 : ('a, int, int) tag
| Tag2 : ('a, string, 'a) tag
type 'a t =
| Foo : ('a, 'b, 'c) tag * 'a * 'b -> 'c t
On Fri, Jul 31, 2015 at 9:48 AM, Ashish Agarwal <agarwal1975@gmail.com>
wrote:
> I have:
>
> type _ t =
> | Foo1 : 'a * int -> int t
> | Foo2 : 'a * string -> 'a t
>
> but I really want to merge these two cases. I want the return type to be
> based on the second arg when the second arg is int, and be based on the
> first arg otherwise. Any way to accomplish that?
>
>
--
Carl Eastlund
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^ permalink raw reply [flat|nested] 7+ messages in thread
* Re: [Caml-list] selecting GADT parameter
2015-07-31 13:57 ` Carl Eastlund
@ 2015-07-31 14:18 ` Ashish Agarwal
2015-07-31 14:31 ` Lukasz Stafiniak
2015-07-31 14:33 ` Runhang Li
0 siblings, 2 replies; 7+ messages in thread
From: Ashish Agarwal @ 2015-07-31 14:18 UTC (permalink / raw)
To: Carl Eastlund; +Cc: Caml List
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You essentially still have 2 constructors, so this isn't quite what I'm
aiming for.
On Fri, Jul 31, 2015 at 9:57 AM, Carl Eastlund <ceastlund@janestreet.com>
wrote:
> Perhaps like this? (Caveat: I typed this straight into gmail, I haven't
> tried to compile or run this code at all.)
>
> type ('a, 'b, 'c) tag =
> | Tag1 : ('a, int, int) tag
> | Tag2 : ('a, string, 'a) tag
>
> type 'a t =
> | Foo : ('a, 'b, 'c) tag * 'a * 'b -> 'c t
>
> On Fri, Jul 31, 2015 at 9:48 AM, Ashish Agarwal <agarwal1975@gmail.com>
> wrote:
>
>> I have:
>>
>> type _ t =
>> | Foo1 : 'a * int -> int t
>> | Foo2 : 'a * string -> 'a t
>>
>> but I really want to merge these two cases. I want the return type to be
>> based on the second arg when the second arg is int, and be based on the
>> first arg otherwise. Any way to accomplish that?
>>
>>
>
>
> --
> Carl Eastlund
>
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* Re: [Caml-list] selecting GADT parameter
2015-07-31 14:18 ` Ashish Agarwal
@ 2015-07-31 14:31 ` Lukasz Stafiniak
2015-07-31 14:33 ` Runhang Li
1 sibling, 0 replies; 7+ messages in thread
From: Lukasz Stafiniak @ 2015-07-31 14:31 UTC (permalink / raw)
To: Ashish Agarwal; +Cc: Carl Eastlund, Caml List
On the face of it, this is not possible. There must be as many pattern
matching branches as there are reachable conditions in the formulation
of the type, because only a pattern matching branch introduces a
conditional (an implication) into reasoning about types. In
particular, you need to pattern match against Tag1 and Tag2 if you
don't want to treat the parameter of the type "t" as an abstract type.
On Fri, Jul 31, 2015 at 4:18 PM, Ashish Agarwal <agarwal1975@gmail.com> wrote:
> You essentially still have 2 constructors, so this isn't quite what I'm
> aiming for.
>
>
> On Fri, Jul 31, 2015 at 9:57 AM, Carl Eastlund <ceastlund@janestreet.com>
> wrote:
>>
>> Perhaps like this? (Caveat: I typed this straight into gmail, I haven't
>> tried to compile or run this code at all.)
>>
>> type ('a, 'b, 'c) tag =
>> | Tag1 : ('a, int, int) tag
>> | Tag2 : ('a, string, 'a) tag
>>
>> type 'a t =
>> | Foo : ('a, 'b, 'c) tag * 'a * 'b -> 'c t
^ permalink raw reply [flat|nested] 7+ messages in thread
* Re: [Caml-list] selecting GADT parameter
2015-07-31 14:18 ` Ashish Agarwal
2015-07-31 14:31 ` Lukasz Stafiniak
@ 2015-07-31 14:33 ` Runhang Li
1 sibling, 0 replies; 7+ messages in thread
From: Runhang Li @ 2015-07-31 14:33 UTC (permalink / raw)
To: Ashish Agarwal; +Cc: Carl Eastlund, Caml List
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Hi,
I don’t think it is possible.
Suppose you can use only one type constructor. What should be the type of function “fun a b -> Foo (a, b)”?
Kindly,
Runhang
On Fri, Jul 31, 2015 at 3:18 PM, Ashish Agarwal <agarwal1975@gmail.com>
wrote:
> You essentially still have 2 constructors, so this isn't quite what I'm
> aiming for.
> On Fri, Jul 31, 2015 at 9:57 AM, Carl Eastlund <ceastlund@janestreet.com>
> wrote:
>> Perhaps like this? (Caveat: I typed this straight into gmail, I haven't
>> tried to compile or run this code at all.)
>>
>> type ('a, 'b, 'c) tag =
>> | Tag1 : ('a, int, int) tag
>> | Tag2 : ('a, string, 'a) tag
>>
>> type 'a t =
>> | Foo : ('a, 'b, 'c) tag * 'a * 'b -> 'c t
>>
>> On Fri, Jul 31, 2015 at 9:48 AM, Ashish Agarwal <agarwal1975@gmail.com>
>> wrote:
>>
>>> I have:
>>>
>>> type _ t =
>>> | Foo1 : 'a * int -> int t
>>> | Foo2 : 'a * string -> 'a t
>>>
>>> but I really want to merge these two cases. I want the return type to be
>>> based on the second arg when the second arg is int, and be based on the
>>> first arg otherwise. Any way to accomplish that?
>>>
>>>
>>
>>
>> --
>> Carl Eastlund
>>
> --
> Caml-list mailing list. Subscription management and archives:
> https://sympa.inria.fr/sympa/arc/caml-list
> Beginner's list: http://groups.yahoo.com/group/ocaml_beginners
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* Re: [Caml-list] selecting GADT parameter
2015-07-31 13:48 [Caml-list] selecting GADT parameter Ashish Agarwal
2015-07-31 13:57 ` Carl Eastlund
@ 2015-08-04 9:21 ` Goswin von Brederlow
2015-08-05 17:26 ` Ashish Agarwal
1 sibling, 1 reply; 7+ messages in thread
From: Goswin von Brederlow @ 2015-08-04 9:21 UTC (permalink / raw)
To: caml-list
On Fri, Jul 31, 2015 at 09:48:13AM -0400, Ashish Agarwal wrote:
> I have:
>
> type _ t =
> | Foo1 : 'a * int -> int t
> | Foo2 : 'a * string -> 'a t
>
> but I really want to merge these two cases. I want the return type to be
> based on the second arg when the second arg is int, and be based on the
> first arg otherwise. Any way to accomplish that?
Say you had (imaginary syntax):
type _ t =
| Foo : 'a * int -> int t
| Foo : 'a * string -> 'a t
let x1 = Foo (1, 1) : int t
let x2 = Foo (1, "x") : int t
match (x : int t) with
| Foo (a, b) -> ...
What is the type of (a, b) now? Is it (int, int) or (int, string)?
MfG
Goswin
^ permalink raw reply [flat|nested] 7+ messages in thread
* Re: [Caml-list] selecting GADT parameter
2015-08-04 9:21 ` Goswin von Brederlow
@ 2015-08-05 17:26 ` Ashish Agarwal
0 siblings, 0 replies; 7+ messages in thread
From: Ashish Agarwal @ 2015-08-05 17:26 UTC (permalink / raw)
To: Goswin von Brederlow; +Cc: Caml List
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Thanks for the answers. I see now the difficulty in this. (Though it seems
possible in theory if we required type annotations in various places.)
On Tue, Aug 4, 2015 at 5:21 AM, Goswin von Brederlow <goswin-v-b@web.de>
wrote:
> On Fri, Jul 31, 2015 at 09:48:13AM -0400, Ashish Agarwal wrote:
> > I have:
> >
> > type _ t =
> > | Foo1 : 'a * int -> int t
> > | Foo2 : 'a * string -> 'a t
> >
> > but I really want to merge these two cases. I want the return type to be
> > based on the second arg when the second arg is int, and be based on the
> > first arg otherwise. Any way to accomplish that?
>
> Say you had (imaginary syntax):
>
> type _ t =
> | Foo : 'a * int -> int t
> | Foo : 'a * string -> 'a t
>
> let x1 = Foo (1, 1) : int t
> let x2 = Foo (1, "x") : int t
>
> match (x : int t) with
> | Foo (a, b) -> ...
>
> What is the type of (a, b) now? Is it (int, int) or (int, string)?
>
> MfG
> Goswin
>
> --
> Caml-list mailing list. Subscription management and archives:
> https://sympa.inria.fr/sympa/arc/caml-list
> Beginner's list: http://groups.yahoo.com/group/ocaml_beginners
> Bug reports: http://caml.inria.fr/bin/caml-bugs
>
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2015-07-31 13:48 [Caml-list] selecting GADT parameter Ashish Agarwal
2015-07-31 13:57 ` Carl Eastlund
2015-07-31 14:18 ` Ashish Agarwal
2015-07-31 14:31 ` Lukasz Stafiniak
2015-07-31 14:33 ` Runhang Li
2015-08-04 9:21 ` Goswin von Brederlow
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