Re: [Caml-list] 'b is unbound

[briand@aracnet.com]

>>>>> "Damien" == Damien  <Damien.Pous@ens-lyon.fr> writes:

  Damien> polymorphic methods require to be explicitly typed (this
  Damien> kind of type inference should lead to the one for system F)

After little more investigation I found that the following will work :

    method op (j:(float, Bigarray.float64_elt, Bigarray.c_layout) Bigarray.Array2.t) f x =

Seems very straightforward.  However there is one confusing aspect :

    method op (j:(float, Bigarray.float64, Bigarray.c_layout) Bigarray.Array2.t) f x =

   error -> Unbound type constructor Bigarray.float64

? Aha ! float64 in bigarray.mli is not a type but a val.

So now my method is no longer polymorphic, right ?


So everything makes sense until I go back to my bigarray test file :

   let a = Bigarray.Array2.create Bigarray.float64 Bigarray.c_layout n n;;

is OK.

   let a = Bigarray.Array2.create Bigarray.float64_elt Bigarray.c_layout n n;;

   error -> Unbound value Bigarray.float64_elt

Then I looked at the definition for create and it finally makes sense.

However I would argue that it is also _very_ confusing.

Why doesn't create simply take the type, i.e. ..._elt instead of 
('a, 'b) kind ??


Brian

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