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From: Pietro Abate <Pietro.Abate@anu.edu.au>
To: ocaml ml <caml-list@inria.fr>
Subject: Re: [Caml-list] (old) camlp4 question
Date: Thu, 12 Apr 2007 11:20:49 +1000	[thread overview]
Message-ID: <20070412012049.GA23847@pulp.rsise.anu.edu.au> (raw)
In-Reply-To: <cd67f63a0704110443l11f977d4ra4b762edf46c1049@mail.gmail.com>

On Wed, Apr 11, 2007 at 01:43:48PM +0200, Nicolas Pouillard wrote:
> Two things:
> The `as' must be surrounded by parentheses  (('b,int) b as 'b).
> And a type declaration is not a type, you can use a str_item or a sig_item.
> Here we go: <:str_item< type a = (b ($list:l$) as 'b) >>;;

Doesn't quite work for me... This is my usage pattern.

I've a toplevel <:str_item< type $list:l$ >> where l is a list of 
((_loc * string),(string * (bool * bool)) list, ctyp ,?? list)
and ?? list is a list of something that I haven't figure out yet (the
manual says <:str_item< type $list:sslt$ >>: type declaration).

to write type a = (b ($list:l$) as 'b) , I've to give a list l
of one element as
((_loc,"a"),[], <:ctyp< (b ($list:[<:ctyp< 'b >>,<:ctyp< int >>]$) as 'b) >>, [])

My problem is to write the type (('b,int) b as 'b) as a ctyp .

I want to write it in this way as both l and the list of type variables
in (('b,int) b as 'b) are not fixed. Moreover types in <:str_item<
type $list:l$ >> can be mutually recursive.

thanks :)
p

-- 
++ Blog: http://blog.rsise.anu.edu.au/?q=pietro
++ 
++ "All great truths begin as blasphemies." -George Bernard Shaw
++ Please avoid sending me Word or PowerPoint attachments.
   See http://www.fsf.org/philosophy/no-word-attachments.html


  reply	other threads:[~2007-04-12  1:20 UTC|newest]

Thread overview: 4+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-04-11 10:59 Pietro Abate
2007-04-11 11:43 ` [Caml-list] " Nicolas Pouillard
2007-04-12  1:20   ` Pietro Abate [this message]
2007-04-12  7:06     ` Nicolas Pouillard

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