caml-list - the Caml user's mailing list
 help / color / mirror / Atom feed
From: Warren Harris <warren@kontiki.com>
To: caml-list@inria.fr
Subject: [Caml-list] module type constraints problem
Date: Wed, 28 May 2003 12:55:38 -0700	[thread overview]
Message-ID: <3ED5143A.4000706@kontiki.com> (raw)

[-- Attachment #1: Type: text/plain, Size: 2446 bytes --]

Hi. I'm wondering if someone on this mailing list can help me with a 
module type problem. What I would like to achieve is an iteration 
abstraction (module) that is parameterized by the node and element type 
of the data to be iterated over. I want to implement this abstraction 
for different data types including lists, and a language expression type.

In the list case, the element type is abstract ('a), and the node type 
is 'a list.

In the expr case, the element type is expr (the exprs themselves, not 
some sub-element of the exprs), and the node type is also expr.

Here's my module type:

    module type Iter =
    sig
      type 'a t
      val iter : ('a -> unit) -> 'a t -> unit
    end

and here's the list implementation (works great):

    module ListIter : Iter =
    struct
      type 'a t = 'a list
      let iter f l = List.iter f l
    end

Here's a simlified version of my expr type:

    type expr =
        Expr of int * expr * expr
      | Int of int
      | Unit

But this implementation of the Iter module won't type check:

    module ExprIter : Iter =
    struct
      type 'a t = expr
      let rec iter f e =
        f e;
        match e with
            Expr(i, a, b) -> iter f a; iter f b
          | e -> ()
    end

    Signature mismatch:
    Modules do not match:
      sig type 'a t = expr val iter : (expr -> 'a) -> expr -> unit end
    is not included in
      Iter
    Values do not match:
      val iter : (expr -> 'a) -> expr -> unit
    is not included in
      val iter : ('a -> unit) -> 'a t -> unit

Adding explicit constraints to the parameters of the iter function don't 
help either:

    module ExprIter : Iter =
    struct
      type 'a t = expr
      let rec iter (f:'a -> unit) (e:'a t) =
        f e;
        match e with
            Expr(i, a, b) -> iter f a; iter f b
          | e -> ()
    end

    Signature mismatch:
    Modules do not match:
      sig type 'a t = expr val iter : (('a t as 'a) -> unit) -> 'a ->
    unit end
    is not included in
      Iter
    Values do not match:
      val iter : (('a t as 'a) -> unit) -> 'a -> unit
    is not included in
      val iter : ('a -> unit) -> 'a t -> unit

Is there some additional way to constrain this problem such that the 
type checker will accept it? If you look closely, 'a t = 'a = expr yet 
the type checker is failing to deduce the equality of the two iter 
function types.

Any help would be greatly appreciated,

Warren

[-- Attachment #2: Type: text/html, Size: 3192 bytes --]

             reply	other threads:[~2003-05-28 19:55 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2003-05-28 19:55 Warren Harris [this message]
2003-05-28 22:49 ` brogoff

Reply instructions:

You may reply publicly to this message via plain-text email
using any one of the following methods:

* Save the following mbox file, import it into your mail client,
  and reply-to-all from there: mbox

  Avoid top-posting and favor interleaved quoting:
  https://en.wikipedia.org/wiki/Posting_style#Interleaved_style

* Reply using the --to, --cc, and --in-reply-to
  switches of git-send-email(1):

  git send-email \
    --in-reply-to=3ED5143A.4000706@kontiki.com \
    --to=warren@kontiki.com \
    --cc=caml-list@inria.fr \
    /path/to/YOUR_REPLY

  https://kernel.org/pub/software/scm/git/docs/git-send-email.html

* If your mail client supports setting the In-Reply-To header
  via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for NNTP newsgroup(s).