"opening" record types

"opening" record types

[Yitzhak Mandelbaum]

[-- Attachment #1: Type: text/plain, Size: 1181 bytes --]

Hi,

I'm generally averse to opening modules, as I find it can make it  
hard to figure out where definitions are coming from. Instead, I  
prefer to bind only those pieces of the module that I need, and to do  
so explicitly.  However, there is one instance in which I find myself  
with little choice: record types.  In order to bind the field- 
constructors for a record, you need to copy the entire type from the  
module in which its declared. For example,

module Foo =
struct
   type t = {a: int; b:int}
end

without copying the type:

let y = {Foo.a=3; Foo.b=4}

with copying:

type t = Foo.t =  {a: int; b:int}

let x = {a=3; b=4}

While this is a nuisance to begin with, its even worse if the record  
type is subject to change -- each time it changes, you need to update  
every place where you copied the definition.

Is there any way around this?  That is, is there any way to use the  
field names of a record defined in another module without opening the  
whole module or copying the whole definition of the record.

Cheers,
Yitzhak

--------------------------------------------------
Yitzhak Mandelbaum
AT&T Labs - Research

http://www.research.att.com/~yitzhak



[-- Attachment #2: Type: text/html, Size: 3938 bytes --]

Re: [Caml-list] "opening" record types

[Olivier Andrieu]

On 8/21/07, Yitzhak Mandelbaum <yitzhak@research.att.com> wrote:
> module Foo =
> struct
>   type t = {a: int; b:int}
> end
>
> without copying the type:
>
> let y = {Foo.a=3; Foo.b=4}

actually, you can write
  let y = {Foo.a=3; b=4}

i.e. you only need the module name on one field of the record, not all

-- 
  Olivier

Re: [Caml-list] "opening" record types

[Yaron Minsky]

[-- Attachment #1: Type: text/plain, Size: 504 bytes --]

On 8/21/07, Olivier Andrieu <oandrieu@gmail.com> wrote:

> actually, you can write
>   let y = {Foo.a=3; b=4}
>
> i.e. you only need the module name on one field of the record, not all


Indeed, at Jane Street, we've come to favor the following idiom:

   let y  = { Module_name.
              field1 = val1;
              field2 = val2;
              ...
            }

The module name then works almost like a constructor, so you hardly need the
syntax extension discussed elsewhere in this thread.

y

[-- Attachment #2: Type: text/html, Size: 1311 bytes --]

Re: [Caml-list] "opening" record types

[Christophe TROESTLER]

On Tue, 21 Aug 2007 09:18:02 -0400, Yitzhak Mandelbaum wrote:
> 
> let y = {Foo.a=3; Foo.b=4}
> 
> Is there any way around this?  That is, is there any way to use the  
> field names of a record defined in another module without opening the  
> whole module or copying the whole definition of the record.

No because the record {a,b} may also be defined in another module and
you need to tell which one to use.  However, you can put the
qualification only once :

let y = {Foo.a=3; b=4}

Of course, if [Foo] name is long, you can alias it at the beginning of
your code :

module F = Very.Long.Module.Name

Cheers,
ChriS

Re: [Caml-list] "opening" record types

[Daniel de Rauglaudre]

Hi,

> Is there any way around this?  That is, is there any way to use the  
> field names of a record defined in another module without opening the  
> whole module or copying the whole definition of the record.

Yes, instead of doing "open Foo", do:

  type t = Foo.t = {a: int; b:int}

-- 
Daniel de Rauglaudre
http://pauillac.inria.fr/~ddr/

Re: [Caml-list] "opening" record types

[Virgile Prevosto]

Hello,

Le mar 21 aoû 2007 09:18:02 CEST,
Yitzhak Mandelbaum <yitzhak@research.att.com> a écrit :

> Is there any way around this?  That is, is there any way to use the  
> field names of a record defined in another module without opening
> the whole module or copying the whole definition of the record.

Olivier Andrieu has written a camlp4 extension (which won't compile
with camlp4 3.10, I'm afraid) that does more or less this:
http://oandrieu.nerim.net/ocaml/index.html#pa_records

It should allow you to write (not tested)

let x = Foo.{a=3; b=4}

-- 
E tutto per oggi, a la prossima volta.
Virgile

Re: [Caml-list] "opening" record types

[Philippe Wang]

Yet another suggestion :

Instead of :
#  module M = struct type t = { a : int ; b : int } end ;;
module M : sig type t = { a : int; b : int; } end

Write :
#  module M = struct type t = { a : int ; b : int } module N = struct 
type t = M.t = { a : int ; b : int } end end ;;
module M :
  sig
    type t = { a : int; b : int; }
    module N : sig type t = M.t = { a : int; b : int; } end
  end

Then :

# include M.N;;
type t = M.t = { a : int; b : int; }

So that you can do :
# { a = 42 ; b = 23 } ;;
- : t = {a = 42; b = 23}

That way, when you change or add definitions, it's easy to spread 
changes, and you export only what you want to export...
:-)

Cheers,

--
Philippe Wang
  mail[at]philippewang.info


Yitzhak Mandelbaum wrote:
> Hi,
>
> I'm generally averse to opening modules, as I find it can make it hard 
> to figure out where definitions are coming from. Instead, I prefer to 
> bind only those pieces of the module that I need, and to do so 
> explicitly.  However, there is one instance in which I find myself 
> with little choice: record types.  In order to bind the 
> field-constructors for a record, you need to copy the entire type from 
> the module in which its declared. For example,
>
> module Foo = 
> struct
>   type t = {a: int; b:int}
> end
>
> without copying the type:
>
> let y = {Foo.a=3; Foo.b=4}
>
> with copying: 
>
> type t = Foo.t =  {a: int; b:int}
>
> let x = {a=3; b=4}
>
> While this is a nuisance to begin with, its even worse if the record 
> type is subject to change -- each time it changes, you need to update 
> every place where you copied the definition.
>
> Is there any way around this?  That is, is there any way to use the 
> field names of a record defined in another module without opening the 
> whole module or copying the whole definition of the record.
>
> Cheers,
> Yitzhak
>
> --------------------------------------------------
> Yitzhak Mandelbaum
> AT&T Labs - Research
>
> http://www.research.att.com/~yitzhak 
> <http://www.research.att.com/%7Eyitzhak>
>
>
> ------------------------------------------------------------------------
>
> _______________________________________________
> Caml-list mailing list. Subscription management:
> http://yquem.inria.fr/cgi-bin/mailman/listinfo/caml-list
> Archives: http://caml.inria.fr
> Beginner's list: http://groups.yahoo.com/group/ocaml_beginners
> Bug reports: http://caml.inria.fr/bin/caml-bugs
>   

Re: [Caml-list] "opening" record types

[Jeremy Yallop]

Philippe Wang wrote:
> Instead of :
> #  module M = struct type t = { a : int ; b : int } end ;;
> module M : sig type t = { a : int; b : int; } end
> 
> Write :
> #  module M = struct type t = { a : int ; b : int } module N = struct 
> type t = M.t = { a : int ; b : int } end end ;;

I don't think this code is quite what you intended.

   # ({a = 0 ; b = 0 } : M.t );;
   Characters 1-17:
      ({a = 0 ; b = 0 } : M.t );;
      ^^^^^^^^^^^^^^^^
   This expression has type t = M.t but is here used with type M.t

I like the idea, though.  You can avoid duplicating the type definition 
by writing the inner module first.

   module M =
   struct
     module N = struct type t = { a : int; b : int } end
     include N
   end

Then, as before:

    open M.N

    { a = 0; b = 0 }

> That way, when you change or add definitions, it's easy to spread 
> changes, and you export only what you want to export...

Yes.  Unforunately, the technique is only useful if you have control of 
the module that you want to import.

Jeremy.