From: Dario Teixeira <dario.teixeira@nleyten.com>
To: Christophe Raffalli <christophe@raffalli.eu>
Cc: caml-list <caml-list@inria.fr>
Subject: Re: [Caml-list] module equality
Date: Tue, 20 Jun 2017 11:03:13 +0100 [thread overview]
Message-ID: <6cd8705bcf05d1cfb4e21d132fd9ee1b@nleyten.com> (raw)
In-Reply-To: <20170620093641.ovz6dnsghtdj6tv6@delli7.univ-savoie.fr>
Hi,
> I thought that two applications of Set.Make to
> the same module would result in two distinct
> modules with two distinct types 't'.
>
> This is not the case, and I am no sure it is a
> good choice as it allows to write the following,
> where you can break the invariant of a functor:
OCaml functors have always been applicative. However,
since 4.02 you can also declare generative functors,
which have the behaviour that you want:
http://caml.inria.fr/pub/docs/manual-ocaml/extn.html#sec253
Hope this helps. Cheers!
Dario Teixeira
next prev parent reply other threads:[~2017-06-20 10:03 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2017-06-20 9:36 Christophe Raffalli
2017-06-20 10:03 ` Dario Teixeira [this message]
2017-06-20 10:05 ` Jeremy Yallop
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