From: Radu Grigore <radugrigore@gmail.com>
To: skaller@users.sourceforge.net
Cc: Stefan Monnier <monnier@iro.umontreal.ca>,
caml-list <caml-list@inria.fr>
Subject: Re: [Caml-list] Re: paralell assignment problem
Date: Tue, 8 Feb 2005 20:33:52 +0200 [thread overview]
Message-ID: <7f8e92aa05020810335ab052e0@mail.gmail.com> (raw)
In-Reply-To: <1107882489.5022.175.camel@pelican.wigram>
On Tue, 08 Feb 2005 09:12:32 -0800 (PST), skaller
<skaller@users.sourceforge.net> wrote:
> However it isn't clear (to me) that just picking an arbitrary
> assignment to split into two using a temporary
> actually minimises the number of temporaries.
I'm mildly convinced that it works.
Imagine a graph where an arrow is drawn from A to B only if A appears
in the expression to be assigned to B. You can imagine the process of
introducing temporaries as marking a few edges in this graph so that
you break all cycles. One marked edge = one temporary. But since no
identifier appears more than once on the left side, in this graph the
in-degree is at most 1 and each node is part of at most one cycle.
>From this it follows that each marked edge breaks at most one cycle.
Since all your temporaries break at least one cycle the algorithm
should work.
--
regards,
radu
http://rgrig.idilis.ro/
next prev parent reply other threads:[~2005-02-08 18:33 UTC|newest]
Thread overview: 17+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-02-08 3:07 skaller
2005-02-08 14:34 ` Stefan Monnier
2005-02-08 16:02 ` [Caml-list] " skaller
2005-02-08 18:20 ` Stefan Monnier
2005-02-08 17:08 ` skaller
2005-02-08 18:33 ` Radu Grigore [this message]
2005-02-09 7:48 ` Radu Grigore
2005-02-09 10:11 ` skaller
2005-02-09 9:43 ` Radu Grigore
2005-02-09 11:19 ` Radu Grigore
2005-02-09 11:34 ` Pascal Zimmer
2005-02-09 13:53 ` skaller
2005-02-08 16:03 ` [Caml-list] " Florian Hars
2005-02-08 17:38 ` skaller
2005-02-08 16:29 ` Marcin 'Qrczak' Kowalczyk
2005-02-08 17:55 ` skaller
2005-02-08 18:32 ` Marcin 'Qrczak' Kowalczyk
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