Re: [Caml-list] polymorphic variant question

[Remi VANICAT <vanicat@labri.u-bordeaux.fr>]

nadji@noos.fr writes:

> Hi all,
>
> I am puzzled by the code below which doesn't work.
>
> # let f = function `B -> ();;
> val f : [ `B] -> unit = <fun>
> # let g x = match (x:[`A|`B]) with `A -> () | y -> f y;;
> Characters 51-52:
>   let g x = match (x:[`A|`B]) with `A -> () | y -> f y;;
>                                                      ^
> This expression has type [ `A | `B] but is here used with type [ `B]
> (denoting the "y" from the "f y")
>
> How can I say to OCaml that "y" can't be of type `A ?

well you can do the following :

let g x = match (x:[`A|`B]) with `A -> () | `B as y -> f y;;

for more complex case, you can do something like :

type b = [ `B ]

let g x = match (x:[`A|`B]) with `A -> () | #b as y -> f y;;

-- 
Rémi Vanicat
vanicat@labri.u-bordeaux.fr
http://dept-info.labri.u-bordeaux.fr/~vanicat
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