Hello, I am at a loss as to the difference between ['a.] syntax and [type a.] syntax of introducing polymorphic recursion. I will provide some examples. (Bear with me, they are automatically generated.) >>> type _ term = | Lit : integer -> integer term | Plus : integer term * integer term -> integer term | IsZero : integer term -> boolean term | If : (*∀'a.*)boolean term * 'a term * 'a term -> 'a term and integer and boolean external plus : (integer -> integer -> integer) = "plus" external is_zero : (integer -> boolean) = "is_zero" external if_then : (boolean -> 'a -> 'a -> 'a) = "if_then" let rec eval : 'a . ('a term -> 'a) = (function Lit i -> i | IsZero x -> is_zero (eval x) | Plus (x, y) -> plus (eval x) (eval y) | If (b, t, e) -> if_then (eval b) (eval t) (eval e)) <<< The above produces: Error: This pattern matches values of type boolean term but a pattern was expected which matches values of type integer term Type boolean is not compatible with type integer but if we replace the corresponding line with: >>> ... let rec eval : type a . (a term -> a) = ... <<< then it compiles fine. Now to a more complex example. According to my understanding (and InvarGenT), the following code should type-check: >>> type _ place = | LocA : a place | LocB : b place and a and b type (_, _) nearby = | Here : (*∀'b.*)'b place * 'b place -> ('b, 'b) nearby | Transitive : (*∀'a, 'b, 'c.*)('a, 'b) nearby * ('b, 'c) nearby -> ('a, 'c) nearby type boolean external is_nearby : (('a, 'b) nearby -> boolean) = "is_nearby" type _ ex1 = | Ex1 : (*∀'a, 'b.*)('b place * ('a, 'b) nearby) -> 'a ex1 external wander : ('a place -> 'a ex1) = "wander" type (_, _) meet = | Same : (*∀'b.*) ('b, 'b) meet | NotSame : (*∀'a, 'b.*) ('a, 'b) meet external compare : ('a place -> 'b place -> ('a, 'b) meet) = "compare" let rec walk : type a b . (a place -> b place -> (a, b) nearby) = (fun x goal -> ((function Same -> Here (x, goal) | NotSame -> let Ex1 ((y, to_y)) = wander x in Transitive (to_y, walk y goal))) (compare x goal)) <<< Here we get Error: This expression has type b place but an expression was expected of type a place Type b is not compatible with type a And when we switch to the ['a.] syntax, we get Error: This definition has type 'a. 'a place -> 'a place -> ('a, 'a) nearby which is less general than 'a 'b. 'a place -> 'b place -> ('a, 'b) nearby Thanks in advance for any thoughts. If you are curious, the source code is: https://github.com/lukstafi/invargent/blob/master/examples/simple_eval.gadt https://github.com/lukstafi/invargent/blob/master/examples/equational_reas.gadt