Sorry about the confusion. I'm taking from one element from each list per
record. The lists can all be arbitrarily long as long as they share the
same length.

lista = [1; 2; 3; 4; 5; 6; 3]
listb = [2; 5; 7; 8; 1; 2; 4]
listc = [4; 6; 8; 3; 5; 8; 2]

type t = {a : int; b: int; c: int}

{a=1; b=2; c=4}
{a=2; b=5; c=6}
{a=3; b=7; c=8}
{a=4; b=8; c=3}
...

I will subscribe to the beginners list as well.

Thanks,
Casey


On Thu, Sep 5, 2013 at 9:46 AM, John Whitington <john@coherentgraphics.co.uk
> wrote:

> Hi Casey,
>
>
> Casey Basichis wrote:
>
>> Hi,
>>
>> I'm new to Ocaml.
>>
>
> There is also this list, for beginners specifically:
>
> http://groups.yahoo.com/neo/**groups/ocaml_beginners/info<http://groups.yahoo.com/neo/groups/ocaml_beginners/info>
>
>
>  I have five lists of ints, how can I can I combine them into a list of
>> records where the fields are filled with values from each of the lists?
>>
>
> Do you mean that the lists are fixed-length, that you have a record type
> something like
>
> type t = {a : int; b : int; c : int; d : int}
>
> and you want to convert each list, which is something like
>
> [1; 2; 3; 4]
>
> into a record something like
>
> {a = 1; b = 2; c = 3; d = 4}
>
> ?
>
>
> In which case, you want to use pattern matching to write a function of type
>
> int list -> t
>
> which converts a (fixed-length) list to a thing of type t and then you can
> use List.map to deal with all your lists, producing a t list from an int
> list list.
>
> If you meant something different entirely, please clarify!
>
> With Thanks,
>
> --
> John Whitington
> Director, Coherent Graphics Ltd
> http://www.coherentpdf.com/
>
>


-- 
Casey James Basichis
Composer - Adventure Time - Cartoon Network
http://www.caseyjamesbasichis.com
caseybasichis@gmail.com
310.387.7540