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From: Dan Stark <interlock.public@gmail.com>
To: Yaron Minsky <yminsky@janestreet.com>
Cc: David House <dhouse@janestreet.com>,
	OCaml Mailing List <caml-list@inria.fr>
Subject: Re: [Caml-list] How is Async implemented?
Date: Wed, 4 Jun 2014 00:51:50 +0100	[thread overview]
Message-ID: <CANQp=sSA17ozwR25dqgBkoutao3dWVN_+Es_3eMr3bmccmmSMg@mail.gmail.com> (raw)
In-Reply-To: <CACLX4jSy=Dby8-Cjpr_a0wMrrJomYz8DU3BZMzXe41m0p4C=bA@mail.gmail.com>

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Hi Yaron

Yes, I do read your book and currently reading this chapter. And this is
the reason I got interested of how it is implemented behind the scene.

Thanks for all the help I got from here.

Dan




On Wed, Jun 4, 2014 at 12:17 AM, Yaron Minsky <yminsky@janestreet.com>
wrote:

> For what it's worth, this gives a decent overview of Async (if I do
> say so myself)
>
>
> https://realworldocaml.org/v1/en/html/concurrent-programming-with-async.html
>
> This isn't quite right, but a good mental model is to think of Async
> as being single threaded.  Scheduler.go starts up the async scheduler
> on the main thread, and you do indeed need to do that for any IO to
> actually happen.
>
> y
>
> On Tue, Jun 3, 2014 at 4:59 PM, Dan Stark <interlock.public@gmail.com>
> wrote:
> > Hi David
> >
> > Thank you very much for this comprehensive explanation.
> >
> > Can I also know who is responsible for the queue and scheduler?
> >
> > Are they created and maintained by OCaml thread (OCaml internal) or Async
> > (3rd party library, which means Async create the job queue and has its
> own
> > scheduler)?
> >
> > In addition, will the compiler got involved in handling Deferred.t?
> >
> > I ask above questions because I felt quite curious about what is
> happening
> > in the followings:
> >
> > Suppose we have a normal function:
> >
> >> let f1 () = print_endline "hello"; whatever_result;;
> >
> >
> > Normally, no matter what whatever_result is, when I do let _ = f1 ();;,
> > print_endline "hello" will be executed, am I right? For example, finally
> > returning an int or a record or a lazy.t, etc, "hello" would be printed
> out.
> >
> > However, if I do
> >
> >> let f2 () = print_endline "hello"; return 1;;
> >
> >
> > let _ = f2 ();; would do nothing unless I run the schedule let _ =
> > ignore(Scheduler.go());;
> >
> > Since for f2 I am not using any other special creation function and the
> only
> > special bit is return 1 after print_endline, if the compiler doesn't get
> > involved, how can compiler know the whole application of f2() should be
> in
> > future execution?
> >
> > Sorry for my above verbose questions if they are boring. I am just
> trying to
> > understand more and I guess eventually I will look into the code once I
> > grasp the big picture.
> >
> > thanks
> >
> > Dan
> >
> >
> >
> >
> >
> >
> >
> >
> >
> > On Tue, Jun 3, 2014 at 5:29 PM, David House <dhouse@janestreet.com>
> wrote:
> >>
> >> There is a queue of jobs in the scheduler. The scheduler runs the jobs
> one
> >> by one. Jobs may schedule other jobs. A job is a pair of ['a * 'a ->
> unit].
> >>
> >> There's a thing called a deferred. ['a Deferred.t] is an initially empty
> >> box that may become filled later with something of type ['a]. There is a
> >> similar type called ['a Ivar.t] -- the difference is that ivars have a
> >> function to actually fill in the value, whereas deferreds do not: a
> deferred
> >> is a "read-only" view on an ivar.
> >>
> >> You can wait on a deferred using bind. Doing [x >>= f] mutates the
> >> deferred x to add f as a "handler". When a deferred is filled, it adds
> a job
> >> to the scheduler for each handler it has.
> >>
> >> Doing [Deferred.return 1] allocates a deferred which is already filled
> and
> >> has no handlers. Binding on that will immediately schedule a job to run
> your
> >> function. (The job is still scheduled though, rather than being run
> >> immediately, to ensure that you don't have an immediate context switch
> -- in
> >> async, the only context switch points are the binds.)
> >>
> >> The primitive operations that block are replaced with functions that
> >> return deferreds, and go do their work in a separate thread. There's a
> >> thread pool to make sure you don't use infinity threads. (I think the
> >> default cap is 50 threads.) I think yes, async does depend on -thread.
> >>
> >> There is an important optimisation: if you want to read or write to
> >> certain file descriptors, that doesn't use a thread. Instead there's a
> >> central list of such file descriptors. There's also a central list of
> all
> >> "timer events" (e.g. deferreds that become deferred after some amount of
> >> time). The scheduler actually is based around a select loop: it does the
> >> following:
> >>
> >> run all the jobs
> >> if more jobs have been scheduled, run those too
> >> keep going until there are no more jobs, or we hit the
> >> maximum-jobs-per-cycle cap
> >> sleep using select until one read fd is read, or a write fd is ready,
> or a
> >> timer event is due to fire
> >> do that thing
> >>
> >> There's also a way to manually interrupt the scheduler. Blocking
> >> operations other than reading/writing to fds do this: they run in a
> thread,
> >> grab the async scheduler lock, fill in an ivar, then wake up the
> scheduler
> >> to ensure timely running of the jobs they just scheduled. The async
> >> scheduler lock is necessary because the scheduler itself is not
> re-entrant:
> >> you cannot have multiple threads modifying the scheduler's internals.
> >>
> >>
> >> On 3 June 2014 16:39, Dan Stark <interlock.public@gmail.com> wrote:
> >>>
> >>> Hi all
> >>>
> >>> I am trying to get a rough overview of how Async is implemented (or the
> >>> idea behind it) before I really dig into its source code.
> >>>
> >>> I have the following questions:
> >>>
> >>> Q1: Is Async event-loop like?
> >>>
> >>> From the API and some docs for Async's usage, I feel it is quite like a
> >>> event-loop.
> >>>
> >>> You create Deferred.t and it might be added to a queue and a scheduler
> >>> behind might be adjusting the order of running for all Deferred.t in
> the
> >>> queue.
> >>>
> >>> Am I correct?
> >>>
> >>> Q2: Deferred.return and Deferred.bind
> >>>
> >>> If I say
> >>>
> >>>> Deferred.return 1
> >>>
> >>>
> >>> It will returns me a Deferred.t, but inside the function return or bind
> >>> somehow an "event" is implicitly added to the default queue for
> scheduling,
> >>> right?
> >>>
> >>> If I am correct above,
> >>>
> >>> Q3: Is Async depending on -thread? The queue or scheduler needs
> compiler
> >>> support?
> >>>
> >>> I just need to understand the whole picture in a rough way first.
> >>>
> >>> Thanks
> >>>
> >>> Dan
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>
> >
>

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      reply	other threads:[~2014-06-03 23:52 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2014-06-03 15:39 Dan Stark
2014-06-03 16:29 ` David House
2014-06-03 20:59   ` Dan Stark
2014-06-03 22:33     ` Ashish Agarwal
2014-06-03 23:17       ` Dan Stark
2014-06-03 23:17     ` Yaron Minsky
2014-06-03 23:51       ` Dan Stark [this message]

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