Hi,
how about that:
# type t = { check : 'a. 'a -> bool };;
type t = { check : 'a. 'a -> bool; }
# let return_true : 'a. 'a -> bool = fun _ -> true;;
val return_true : 'a -> bool = <fun>
# let make1 () = { check = return_true; };;
val make1 : unit -> t = <fun>
cheers,
Philippe.
Hello.
I am trying to build a record with a polymorphic field and I am unable to initialize this field. The problem can be summarized as follow. The following definitions works well:
type t = { check : 'a. 'a -> bool }
let return_true _ = true
let make1 () = { check = return_true; }
But this definition raises an error:
let make2 f = { check = f; }
with the message:
Error: This field value has type 'a -> bool which is less general than
'b. 'b -> bool
Note that
let return_false _ = true
let make3 c = { check = if c then return_false else return_true; }
is working but that
let g c = if c then return_false else return_true
let make4 c = { check = g c; }
raises the same error message. Making explicit the argument of make does not helps:
let make5 f = { check = f; }
in make5 return_true
(same error message). And making explicit the type of make does not help neither:
let make6 : 'a. ('a -> bool) -> t
= function f -> { check = f; }
(same error message).
Do you have an idea how I can specify a function similar to make to buid a record of type t?
In the real life, the argument f will be the result of a computation and instead of a simple signature 'a -> bool, I must deal with a signature
'a 'b. (('b) #SomeClass as 'a) * 'b -> bool
Thanks for your advice,
Jean-Louis Giavitto.
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