Hi,

how about that:

# type t = { check : 'a. 'a -> bool };;                                        
type t = { check : 'a. 'a -> bool; }                                           

# let return_true : 'a. 'a -> bool = fun _ -> true;;                           
val return_true : 'a -> bool = <fun>                                           

# let make1 () = { check = return_true; };;                                    
val make1 : unit -> t = <fun>                                                  

cheers,
  Philippe.


2012/7/3 Jean-Louis Giavitto <jean-louis.giavitto@ircam.fr>
Hello.

I am trying to build a record with a polymorphic field and I am unable to initialize this field. The problem can be summarized as follow. The following definitions works well:

   type t = { check : 'a. 'a -> bool }

   let return_true _ = true

   let make1 () = { check = return_true; }

But this definition raises an error:

   let make2 f = { check = f; }

with the message:

  Error: This field value has type 'a -> bool which is less general than
         'b. 'b -> bool

Note that

   let return_false _ = true

   let make3 c = { check = if c then return_false else return_true; }

is working but that

   let g c = if c then return_false else return_true
   let make4 c = { check = g c; }

raises the same error message. Making explicit the argument of make does not helps:

  let make5 f = { check = f; }
  in make5 return_true

(same error message). And making explicit the type of make does not help neither:

  let make6 : 'a. ('a -> bool) -> t
  = function f -> { check = f; }

(same error message).



Do you have an idea how I can specify a function similar to make to buid a record of type t?

In the real life, the argument f will be the result of a computation and instead of a simple signature 'a -> bool, I must deal with a signature

   'a 'b. (('b) #SomeClass as 'a) * 'b -> bool


Thanks for your advice,
Jean-Louis Giavitto.

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