From: Lukasz Lew <ll189417@zodiac.mimuw.edu.pl>
To: caml-list@inria.fr
Subject: [Caml-list] Syntax error
Date: Wed, 4 Jun 2003 11:19:47 +0200 (CEST) [thread overview]
Message-ID: <Pine.LNX.4.44.0306041105490.22712-100000@zodiac.mimuw.edu.pl> (raw)
In-Reply-To: <941EB0B0-91BE-11D7-B411-000393B9096C@is.titech.ac.jp>
Hi.
I am using Genlex and ocaml streams and parsers. And when I catch
exception Stream.Error "", I can not generate other message than "syntax error".
How can I obtain informations about line number or character number,
where the error ocurred ?
In ocaml examples at http://caml.inria.fr/Examples/oc.tar.gz, function
pos_in is used, but it returns always number of last character in stream.
Do you have any ideas?
And how ocamlyacc deals with this problem?
Regards,
Lukasz Lew
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next prev parent reply other threads:[~2003-06-04 9:19 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-05-28 21:03 [Caml-list] Ocamllex/Ocamlyacc feature request Brian Hurt
2003-05-29 10:16 ` Ken Wakita
2003-05-29 12:03 ` Damien
2003-05-29 13:07 ` Luc Maranget
2003-06-04 9:19 ` Lukasz Lew [this message]
2003-06-04 17:25 ` [Caml-list] Syntax error Stefan Heimann
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