From: Peter Selinger <selinger@math.lsa.umich.edu>
To: T.Leinster@dpmms.cam.ac.uk (Tom Leinster)
Cc: categories@mta.ca
Subject: Re: Re: one-object closed categories
Date: Fri, 11 Dec 1998 22:15:22 -0500 (EST) [thread overview]
Message-ID: <199812120315.WAA01623@dirichlet.math.lsa.umich.edu> (raw)
In-Reply-To: <E0zoBd6-0001sC-00@carp.dpmms.cam.ac.uk> from "Tom Leinster" at Dec 10, 98 07:20:03 pm
> From Tom Leinster:
>
> Since I asked the question I've found a few examples; they've all got
> the same flavour about them, so I'll just do my favourite.
>
> If V is the commutative monoid, then a V-enriched category is a set A plus
> two functions
> [-,-,-]: A x A x A ---> V
> [-]: A ---> V
> satisfying
> [a,c,d] + [a,b,c] = [a,b,d] + [b,c,d]
> [a,a,b] + [a] = 0 = [a,b,b] + [b]
> for all a, b, c, d.
A few remarks: In the case where V is an abelian group, the first
axiom already implies the other two if we define [a] = -[a,a,a].
Namely, by letting a=b in the first axiom, it follows that [a,a,c] is
independent of c.
If V is an abelian group, then one can get an example of the above
structure from an arbitrary map {-,-} : A x A ---> V by letting
[a,b,c] = {a,b}+{b,c}-{a,c} and [a] = -{a,a}. Tom's "area" example is
of this form.
In fact, if V is an abelian group, then *any* example of a V-enriched
category is (non-uniquely) of the form described in the previous
paragraph: Fix some x in A (if any), and define {a,b} = [a,b,x].
What about the non-group case? In general, [a,b,c] need not always be
invertible in V. In fact, [a,b,a] need not be invertible. For a simple
example of this, let V be the natural numbers and define
[a] = 0,
[a,b,c] = 0, if a=b or b=c,
1, if a,b,c pairwise distinct,
2, otherwise (i.e., if a=c but a,b distinct).
This indeed works.
Best wishes,
-- Peter Selinger
> The example: let A be a subset of the plane. Choose a smooth path P(a,b) from
> a to b for each (a,b) in A x A, and define [a,b,c] to be the signed area
> bounded by the loop
> P(a,b) then P(b,c) then (P(a,c) run backwards);
> also define [a] to be
> -(area bounded by P(a,a)).
> (There's meant to be an orientation on the plane, so that areas can be
> negative.) Then the equations say obvious things about area - don't think
> I'm up to that kind of ASCII art, though.
next prev parent reply other threads:[~1998-12-12 3:15 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
1998-12-10 19:20 Tom Leinster
1998-12-12 3:15 ` Peter Selinger [this message]
1998-12-12 21:31 ` Mamuka Jibladze
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