From: Vaughan Pratt <pratt@CS.Stanford.EDU>
To: categories@mta.ca
Subject: re: Query (Q-algebras)
Date: Wed, 07 May 2003 11:55:08 -0700 [thread overview]
Message-ID: <200305071855.LAA22674@coraki.Stanford.EDU> (raw)
In-Reply-To: Message from Oswald Wyler <owyler@suscom-maine.net> of "Mon, 05 May 2003 13:46:43 EDT." <Pine.LNX.4.44.0305051343560.1296-100000@192-173.suscom-maine.net>
The operations of Q-alg are the functions between the powers of the set Z,
forming the (Lawvere) theory T of Q-algebras, which are product-preserving
functors from T to Set. (So if Z is 3 then there are 27 = 3^3 "Boolean"
operations in place of the familiar 4 = 2^2.) With all powers Q-algebras are
equivalent to CABAs, with only finite powers and finite-product-preserving
functors they are equivalent to Boolean algebras.
A natural next question would be, what is obtained when T is taken to be
Set itself, in each of the cases when the functors T->Set are required to
preserve all limits, and just the discrete ones?
Vaughan Pratt
>From: Oswald Wyler <owyler@suscom-maine.net>
>For every set Z, there is a self-adjoint contravariant functor Q=ENS(--,Z),
>with unit/counit h:Id-->Q^op Q given by (h_X)(x)(f)=f(x). Let Q-alg denote
>the category of algebras for the monad induced by this self-adjunction.
>If Z is not empty or a singleton, then the comparison functor ENS^op-->Q-alg
>is an equivalence by results of M. Sobral. If Z has two members, then Q-alg
>is isomorphic to CaBool, the category of complete atomic Boolean algebras.
>What is known about Q-alg if Z has more than two members (beyond the fact
>that Q-alg and CaBool are equivalent)?
next prev parent reply other threads:[~2003-05-07 18:55 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <owyler@suscom-maine.net>
2003-05-05 17:46 ` Query Oswald Wyler
2003-05-07 18:55 ` Vaughan Pratt [this message]
2003-05-08 19:05 ` Query (Q-algebras) Vaughan Pratt
2003-05-09 11:24 ` Ernie Manes
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