From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.io/gmane.science.mathematics.categories/3474 Path: news.gmane.org!not-for-mail From: Steve Vickers Newsgroups: gmane.science.mathematics.categories Subject: Re: Characterization of integers as a commutative ring with unit Date: Thu, 26 Oct 2006 15:48:52 +0100 Message-ID: NNTP-Posting-Host: main.gmane.org Mime-Version: 1.0 (Apple Message framework v752.2) Content-Type: text/plain; charset=US-ASCII; delsp=yes; format=flowed Content-Transfer-Encoding: 7bit X-Trace: ger.gmane.org 1241019328 8922 80.91.229.2 (29 Apr 2009 15:35:28 GMT) X-Complaints-To: usenet@ger.gmane.org NNTP-Posting-Date: Wed, 29 Apr 2009 15:35:28 +0000 (UTC) To: categories@mta.ca Original-X-From: rrosebru@mta.ca Thu Oct 26 21:39:05 2006 -0300 Return-path: Envelope-to: categories-list@mta.ca Delivery-date: Thu, 26 Oct 2006 21:39:05 -0300 Original-Received: from Majordom by mailserv.mta.ca with local (Exim 4.61) (envelope-from ) id 1GdFef-0002lZ-Jl for categories-list@mta.ca; Thu, 26 Oct 2006 21:33:01 -0300 Original-Sender: cat-dist@mta.ca Precedence: bulk X-Keywords: X-UID: 37 Original-Lines: 49 Xref: news.gmane.org gmane.science.mathematics.categories:3474 Archived-At: Dear Andrej, Z is the initial ring with unit. (Doesn't matter whether you require commutativity.) It's not clear to me why you felt the need to say "non-trivial" in (3). Regards, Steve. On 26 Oct 2006, at 09:56, Andrej Bauer wrote: > For the purposes of defining the data structure of integers in a > Coq-like system, I am looking for an _algebraic_ characterization of > integers Z as a commutative ring with unit. (The one-element ring is a > ring.) > > Some possible characterizations which I don't much like: > > 1) Z is the free group generated by one generator. I want the ring > structure, not the group structure. > > 2) Z is the free ring generated by the semiring of natural numbers. > This > just translates the problem to characterization of the semiring of > natural numbers. > > 3) Z is the initial non-trivial ring. This is no good because > "non-trivial" is an inequality "0 =/= 1" rather than an equality. > > 4) Let R be the free commutative ring with unit generated by X. Then Z > is the image of the homomorphism R --> R which maps X to 0. This is > just > ugly and there must be something better. > > I feel like I am missing something obvious. Surely Z appears as a > prominent member of the category of commutative rings with unit, > does it > not? > > Best regards, > > Andrej > >