From: Vaughan Pratt <pratt@cs.stanford.edu>
To: Categories list <categories@mta.ca>
Subject: Re: A question on adjoints
Date: Tue, 18 Mar 2008 22:43:35 -0700 [thread overview]
Message-ID: <E1Jc2mT-00015Y-P2@mailserv.mta.ca> (raw)
Isn't the following a counterexample?
Let A = Set and let B = A\{0} (the category of nonempty sets). Let F
send the empty set in A to the singleton set in B, and otherwise let F
and U be the evident identity functors between A and B. Similarly let
\eta and \epsilon be the identity natural transformations, except for
\eta_0 which can only be the unique function from 0 to 1. Naturality
of \eta and \epsilon depends on both being the identity, except for
\eta_0 but that's from the initial object so all its diagrams commute.
Then 0 equalizes the two arrows from U1 to U2 but \eta_0 does not
equalize UF\eta a and \eta UFa since the latter two are both 1_1 in A
whence they are equalized by 1.
Vaughan
Michael Barr wrote:
> I guess I am getting old and dumb. This question should have been a snap
> for me years ago. It is old fashioned, only a 1-categorical question and
> not about internal vs. external.
>
> Suppose F: A --> B is left adjoint to U: B --> A. Suppose a is an object
> of A and b, b' objects of B such that there is an equalizer
> a ---> Ub ===> Ub'. (The two arrows Ub to UB' are not assumed to be U
> of arrows from B.) Does it follow that a ---> UFa ===> UFUFa is an
> equalizer? The arrows are \eta a, UF\eta a and \eta UFa of course.
>
> Michael
>
>
next reply other threads:[~2008-03-19 5:43 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-03-19 5:43 Vaughan Pratt [this message]
-- strict thread matches above, loose matches on Subject: below --
2008-03-19 23:41 Vaughan Pratt
2008-03-19 18:43 Michael Barr
2008-03-18 18:11 Michael Barr
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