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From: Michael Shulman <shulman@math.uchicago.edu>
To: categories <categories@mta.ca>
Subject: Re: biadjoint biequivalences and spans in 2-categories
Date: Tue, 19 Aug 2008 13:11:10 -0500	[thread overview]
Message-ID: <E1KVc4Z-0004fG-Vk@mailserv.mta.ca> (raw)

Hi John,

Answers to both this and your previous question about biadjoint
biequivalences are at least asserted in Street's "Fibrations in
Bicategories".

At the end of section 1, he defines a functor (=homomorphism) to have a
left biadjoint if each object has a left bilifting, to be a biequivalence
if it is biessentially surjective and locally fully faithful, and states
that "clearly a biequivalence T has a left biadjoint S which is also a
biequivalence".

At the beginning of section 3 he defines a bicategory of spans from A to
B in any bicategory, and given finite bilimits, essentially describes
how to construct what one might call an "unbiased tricategory" of spans
(of course, the definition of tricategory didn't exist at the time).

He doesn't give any details of the proofs, but one could probably
construct a detailed proof from these ideas without much more than
tedium.  I don't know whether anyone has written them out.

Best,
Mike

On Tue, Aug 19, 2008 at 07:45:12AM -0700, John Baez wrote:
> Dear Categorists -
>
> Given a category C with pullbacks we can define a bicategory Span(C)
> where objects are objects of C, morphisms are spans - composed
> using pullback - and 2-morphisms are maps between spans.
>
> Have people tried to categorify this yet?
>
> Suppose we have a 2-category C with pseudo-pullbacks.  Then we should
> be able to define a tricategory Span(C).   Has someone done this?
>
> Or maybe people have gotten some partial results, e.g. in the case
> where C = Cat.  I'd like to know about these!
>
> Best,
> jb
>
>
>
>




             reply	other threads:[~2008-08-19 18:11 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2008-08-19 18:11 Michael Shulman [this message]
2008-08-20  6:56 Richard Garner
2008-08-20  9:04 Tom Fiore

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