From: Marco Grandis <grandis@dima.unige.it>
To: George Janelidze <janelg@telkomsa.net>, categories@mta.ca
Subject: Re: Question on exact sequence (by G.J.)
Date: Thu, 12 Nov 2009 09:12:47 +0100 [thread overview]
Message-ID: <E1N8cyu-0000CN-VF@mailserv.mta.ca> (raw)
In-Reply-To: <027601ca62f9$ace359c0$0b00000a@C3>
Dear George,
I receive now your question.
> The Barr's case (=Exercise VIII.4.6 in Mac Lane's book) and the
> Snake Lemma
> seem to have very different canonical connecting morphisms; how
> does your
> (beautiful!) general theorem solve this problem?
All these connecting morphisms are canonically induced on
subquotients, there is
no need of using relations (even though you can, in both cases: a
subquotient
is the same as a subobject in the cat. of relations, and induced
morphisms can
always be computed that way: this is already in Mac Lane's Homology.)
In the Snake Lemma, with Barr's notation:
- Ker h is a subquotient of B (being a subobject of C),
- Cok f is a subquotient of B' (being a quotient of A'),
- the connecting morphism is induced by g: B --> B'.
In the other lemma (Mac Lane, Barr), Ker h and Cok h are both
subquotients
of the middle object, and the (obvious) connecting morphism is
(trivially) induced
by the identity of the latter.
Subquotients are characterised by a pullback-pushout square
with two monos and two epis (in abelian categories;
more generally in the Puppe-exact ones; more generally in
'my' homological categories, where you do not have relations).
'Regular' induction just means that there is a commutative cube
from the first square to the second.
Best wishes Marco
[For admin and other information see: http://www.mta.ca/~cat-dist/ ]
prev parent reply other threads:[~2009-11-12 8:12 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-11-11 11:05 Question on exact sequence Steve Lack
2009-11-11 16:36 ` George Janelidze
[not found] ` <E258C2F0-8620-4CD8-8011-B544D44C95BD@dima.unige.it>
[not found] ` <027601ca62f9$ace359c0$0b00000a@C3>
2009-11-12 8:12 ` Marco Grandis [this message]
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