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* Re: "Semi-additive" seems to be it
@ 2012-01-09  8:47 bourn
  2012-01-09 19:39 ` Robin Cockett
                   ` (2 more replies)
  0 siblings, 3 replies; 11+ messages in thread
From: bourn @ 2012-01-09  8:47 UTC (permalink / raw)
  To: George Janelidze; +Cc: Categories list

Dear all,

I completely agree with George.

By the way, I studied such kind of categories (among others) in:
"Intrinsic centrality and associated classifying properties"
J. of Algebra, 256, 2002, 126-145.
I called them "linear", following Lawvere and Schanuel's "Conceptual
Mathematics".

Truly yours,

Dominique

I agree with


> May I try to protest against "plurality"?
>
> My reason of suggesting "half-" and not "semi-" is "semi-abelian". I
understand that "semi-" is suggested by "semigroup", but "semi-abelian"
was
> suggested by "semidirect products". Note that "semidirect products" are
defined categorically and a semi-abelian category is abelian if and only
if
> its semidirect products coincide with direct (that is, cartesian) products.
>
> Similarly, if a category with finite coproducts merely has semidirect
products, then it is additive if and only if its semidirect products
coincide with direct products.
>
> Another reason against
>
> "semi-additive = enriched in commutative monoids + has finite products"
>
> is that we do not want to identify monoids with semigroups, do we?
>
> And, surely, instead of saying that
>
> "While the category of commutative monoids is a motivating example of a
semi-additive category, the category of commutative semigroups is not
semi-additive"
>
> it is much better to say that
>
> "Semi- refers to semidirect products and not to semigroups".
>
> I hope to get support even from those who already made the opposite
suggestion...
>
> George
>
> P.S. Well, I always try to respect old terminology, but sometimes (what  can
> we do?) it is better to change it. By the way, many years ago Dmitrii
Raikov
> introduced another notion of "semi-abelian". As it turned out with help
of
> Yaroslav Kopylov, that Raikov semi-abelian means
>
> additive + regular + coregular
>
> It is an important notion with interesting examples, but what we call
semi-abelian today seemed to be so much more suitable to call
> "semi-abelian"!
>
>
> --------------------------------------------------
> From: "Michael Barr" <barr@math.mcgill.ca>
> Sent: Saturday, January 07, 2012 2:38 PM
> To: "Categories list" <categories@mta.ca>
> Subject: categories: "Semi-additive" seems to be it
>
>> Thanks for all the replies, but while there was consensus,
>> "semi-additive"
>> got a plurality and we will go with that.
>> Michael
>> --
>> Any society that would give up a little liberty to gain a little
security will deserve neither and lose both.
>>             Benjamin Franklin
>> [For admin and other information see: http://www.mta.ca/~cat-dist/ ]
>
>
>
> [For admin and other information see: http://www.mta.ca/~cat-dist/ ]
>






[For admin and other information see: http://www.mta.ca/~cat-dist/ ]


^ permalink raw reply	[flat|nested] 11+ messages in thread
* Re: What about biproducts?
@ 2012-01-14 22:22 Fred E.J. Linton
  2012-01-16  7:42 ` Vaughan Pratt
       [not found] ` <E1RmmcB-0001xh-CW@mlist.mta.ca>
  0 siblings, 2 replies; 11+ messages in thread
From: Fred E.J. Linton @ 2012-01-14 22:22 UTC (permalink / raw)
  To: categories; +Cc: George Janelidze

On Sat, 14 Jan 2012 09:51:24 AM EST, George Janelidze <janelg@telkomsa.net>
wrote:

> ... What about biproducts? ...
>
> ... [snip] ...
>
> (b) if a category admits infinite biproducts, then it is indiscrete (=every
> object in it is zero) ...

Let me refute that by channeling the voice of Dana May Latch, the late 
Alex Heller's student-of-yore, who stumped me once, decades ago, by asking:

: What do you call a category where products and coproducts coincide?

I confessed I had no idea, I had not even an example of that phenomenon,
and she immediately offered the example (which I hereby share with George)
of sup-complete sup-semilattices (with bottom element (of course)), and
sup (and bottom-element) -preserving maps.

If L_i are such semilattices, with bottom elements 0_i, and L is their 
product, with projections p_i: L --> L_i, the functions j_i: L_i --> L
defined by p_n(j_i) = id_L_i (n=i), p_n(j_i) = 0_n (otherwise) display
the product L as a coproduct of the L_i.

Indeed, given a family of sup-preserving maps f_i: L_i --> T to a 
sup-complete test sup-semilattice T, the solution f: L --> T to the
associated universal mapping problem j_i(f) = f_i is given simply by

f(l) = f((..., l_i, ...)) = sup_i(f_i(l_i)) (l = (..., l_i, ...) &isin; L).

In fact, one may thus even see id_L as the sup of all the compositions
j_i(p_i), much as happens (using addition) for the biproduct of modules,
only using not addition but the infinitary "N-linear" or "semi-additive" 
structure relevant to the category of sup-complete sup-semilatiices.

Even more, as Dana May knew already back whenever that was, the
examples of &aleph;-complete sup-semilattices illustrate that one can 
have categories in which products and coproducts of up to &aleph; objects
coincide, but larger ones differ -- for pretty much any &aleph; (by
"pretty much any" should I probably mean "any regular cardinal", i.e., 
any cardinal not the sum of fewer smaller cardinals? I'm not sure).

If Dana May is lurking in the background, reading these communications,
I'd sure be glad to learn more from her what finally became of the line
of thinking these considerations were part of, and what terminology she
settled on for such "infinite biproducts" and for categories having them.

Cheers, -- Fred Linton



[For admin and other information see: http://www.mta.ca/~cat-dist/ ]


^ permalink raw reply	[flat|nested] 11+ messages in thread

end of thread, other threads:[~2012-01-16 19:52 UTC | newest]

Thread overview: 11+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2012-01-09  8:47 "Semi-additive" seems to be it bourn
2012-01-09 19:39 ` Robin Cockett
2012-01-13 23:36   ` What about biproducts? George Janelidze
2012-01-14 20:12     ` Michael Barr
2012-01-14 21:13     ` rlk
2012-01-10  2:35 ` "Semi-additive" seems to be it Ross Street
2012-01-10 15:07   ` Todd Trimble
     [not found] ` <E1Rm52K-0002ko-Nm@mlist.mta.ca>
2012-01-16  9:41   ` What about biproducts? Vaughan Pratt
2012-01-14 22:22 Fred E.J. Linton
2012-01-16  7:42 ` Vaughan Pratt
     [not found] ` <E1RmmcB-0001xh-CW@mlist.mta.ca>
2012-01-16 19:52   ` Vaughan Pratt

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