Re: mailcap-viewer-lessp is just plain wrong

[Mark Buda <hermit@clark.net>]

>>>>> "ZSH" == Shenghuo ZHU <zsh@cs.rochester.edu> writes:

    Mark> Even if mine isn't right, the existing function is just
    Mark> wrong. How can X be better if only one is wild, regardless
    Mark> of which one is wild?

    ZSH> Your argument is right, but I don't think yours function is right. In
    ZSH> the case that both X and Y are lisp, X is wild, while Y is not wild,
    ZSH> your function returns 't. How can X be better than Y?

    ZSH> Another problem is, in the case that X is wild and list, Y is neither
    ZSH> wild nor list, both evaluations of (mailcap-viewer-lessp x y) and
    ZSH> (mailcap-viewer-lessp y x) return 't for both the functions.

Well, by better I meant that mine produced the correct value in the
case I was concerned about :-) Perhaps I miscopied something from my
sheet of paper (which I threw out, so I'll never know). This should be
right, though. Better, anyway.

(cond
 ; if only one is wild, the other one is better
 ((and x-wild (not y-wild))
  nil)
 ((and (not x-wild) y-wild)
  t)
 ; otherwise, if only one is lisp, it is better
 ((and x-lisp (not y-lisp))
  t)
 ((and (not x-lisp) y-lisp)
  nil)
 ; otherwise, compare them some other arbitrary way
 (t
  (blah blah blah)))
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