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"Davide G. M. Salvetti" <salve@debian.org> writes:

>>>>>> "PJ" == Paul Jarc <prj@po.cwru.edu> writes:
> 
> PJ> '(lambda ...) is equivalent to (lambda ...).
> 
> Oh, I really thought that (lambda ...) was equivalent to (function
> (lambda ...)), which in turn also has the read syntax #'(lambda ...).

You're right.  Look at the definition of lambda, which is a macro, to
see.

> Are you really sure that (lambda ...) evaluates to (quote (lambda ...))
> rather than to (function (lambda ...))?

I believe Paul's wrong here.

Sam