From: Seweryn Kokot <s.kokot@po.opole.pl>
To: ding@gnus.org
Cc: reader@newsguy.com
Subject: Re: How to reply to posts?
Date: Wed, 28 May 2008 19:55:06 +0200 [thread overview]
Message-ID: <878wxu1fgl.fsf@poczta.po.opole.pl> (raw)
In-Reply-To: <87tzgiuyw2.fsf@newsguy.com>
reader@newsguy.com writes:
> I tried this on this post so I guess you will know if it works if you
> also get a CC of it.
>
> I did this:
> F <Followup> (on the desired message in this gmane newsgroup)
> Once inside the followup window:
>
> pressed C-c C-f C-c
> `message-goto-cc'
>
> Which adds a new blank header to the message:
> `Cc:'
>
> Then inserted your email.
Thanks, it works. A small inconvenience is the need to copy and yank
email address when it's not in bbdb, but I can live with that.
regards,
--
Seweryn Kokot
prev parent reply other threads:[~2008-05-28 17:55 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-05-27 18:15 Seweryn Kokot
2008-05-27 20:52 ` Reiner Steib
2008-05-28 17:22 ` reader
2008-05-28 17:55 ` Seweryn Kokot [this message]
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=878wxu1fgl.fsf@poczta.po.opole.pl \
--to=s.kokot@po.opole.pl \
--cc=ding@gnus.org \
--cc=reader@newsguy.com \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for NNTP newsgroup(s).