Re: nnimap-generate-folder-list-from-bbdb, almost.

[Uwe Brauer <oub@mat.ucm.es>]

>>>>> "Ted" == Ted Zlatanov <tzz@lifelogs.com> writes:

    Ted> On Wed, 23 Feb 2005, oub@mat.ucm.es wrote:

    Ted> You can use a macro to do this.

    Ted> For example (from the manual, see the ELisp manual, node "Macros"):

    Ted>     '(a list of (+ 2 3) elements)
    Ted>           => (a list of (+ 2 3) elements)
    Ted>     `(a list of (+ 2 3) elements)
    Ted>           => (a list of (+ 2 3) elements)
    Ted>      `(a list of ,(+ 2 3) elements)
    Ted>           => (a list of 5 elements)

Great I did not know about this.
    Ted> Note how the backquote turns the expression into a macro.

    Ted> So it seems that in your case, something like this:

    Ted> (setq nnimap-split-fancy
    Ted>  `(|
    Ted>    ("Subject" "POSIBLE SPAM" "SPAM.POSS")
    Ted> ...
    Ted>   ,(my:nnimap-folder-list-from-bbdb)
    Ted> ...
    Ted>   "MAILBOX"
    Ted>   ))

    Ted> should work.
Almost almost.

I works when (my:nnimap-folder-list-from-bbdb) would just return one
entry however if there are more the above setting leads to 
`nnimap-split-fancy' is a variable declared in Lisp.
  -- loaded from "nnimap"

Value: (| 
(("From" "oub@gmx\\.net" "imapgmx") 
^evil par
        ("From" "oub@mat\\.ucm\\.es" "testimap")) 
                                                ^evil par
("Subject" ".*\\[POSSILBLE
SPAM\\].*" "SPAM.POSS")
and this is evil


So I was pointed out that    ,(car (my:nnimap-folder-list-from-bbdb))
might, work, it does, but of course it will add only *the first*  of the above
list entries not all of them. Lisp is made to deal with lists, but
how?

Thanks

Uwe