From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.io/gmane.emacs.gnus.general/27176 Path: main.gmane.org!not-for-mail From: Jeff Senn Newsgroups: gmane.emacs.gnus.general Subject: Re: Cups Date: 23 Nov 1999 13:31:13 -0500 Organization: MAYA Design Group Sender: owner-ding@hpc.uh.edu Message-ID: References: <87aeo5xjuv.fsf@twocups.sirinet.net> NNTP-Posting-Host: coloc-standby.netfonds.no Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii X-Trace: main.gmane.org 1035164250 23247 80.91.224.250 (21 Oct 2002 01:37:30 GMT) X-Complaints-To: usenet@main.gmane.org NNTP-Posting-Date: Mon, 21 Oct 2002 01:37:30 +0000 (UTC) Return-Path: Original-Received: from bart.math.uh.edu (bart.math.uh.edu [129.7.128.48]) by sclp3.sclp.com (8.8.5/8.8.5) with ESMTP id NAA15990 for ; Tue, 23 Nov 1999 13:34:44 -0500 (EST) Original-Received: from sina.hpc.uh.edu (lists@Sina.HPC.UH.EDU [129.7.3.5]) by bart.math.uh.edu (8.9.1/8.9.1) with ESMTP id MAB15803; Tue, 23 Nov 1999 12:34:22 -0600 (CST) Original-Received: by sina.hpc.uh.edu (TLB v0.09a (1.20 tibbs 1996/10/09 22:03:07)); Tue, 23 Nov 1999 12:32:01 -0600 (CST) Original-Received: from sclp3.sclp.com (root@sclp3.sclp.com [204.252.123.139]) by sina.hpc.uh.edu (8.9.3/8.9.3) with ESMTP id MAA01249 for ; Tue, 23 Nov 1999 12:31:45 -0600 (CST) Original-Received: from pigeon.maya.com (postfix@po.maya.com [192.70.254.2]) by sclp3.sclp.com (8.8.5/8.8.5) with ESMTP id NAA15909 for ; Tue, 23 Nov 1999 13:31:09 -0500 (EST) Original-Received: from SNIPE.maya.com (snipe.maya.com [192.70.254.125]) by pigeon.maya.com (Postfix) with ESMTP id 306173ED5; Tue, 23 Nov 1999 13:23:11 -0500 (EST) Original-To: ding@gnus.org In-Reply-To: Wes Hardaker's message of "23 Nov 1999 09:42:04 -0800" Original-Lines: 20 User-Agent: Gnus/5.070099 (Pterodactyl Gnus v0.99) Emacs/20.4 Precedence: list X-Majordomo: 1.94.jlt7 Xref: main.gmane.org gmane.emacs.gnus.general:27176 X-Report-Spam: http://spam.gmane.org/gmane.emacs.gnus.general:27176 Wes Hardaker writes: > >>>>> On 23 Nov 1999 10:18:00 -0600, Bud Rogers said: > Bud> Hmm, (desperately tries to remember high school geography > Bud> lessons), circumference of the earth is about 25,000 mi. or > Bud> 40,000 km. Terminator speed would be a bit more than 1,000 mph > Bud> or a bit less that 1,700 kph. Sound reasonable? > > A- (An exact answer would have gotten an A+) As someone said, it depends on your latitude: off the top of my head I'd say you have to go at most: 1666.67 * cos(abs(lat)) KPH [Assuming you started at least 1666.67 km in the correct direction from the initial event and maintain constant speed to the west :-)] -- -Jas