Hi,

From the HoTT book, the truncation of any type A has two constructors:

1) for any a : A, there is |a| : ||A||
2) for any x,y : ||A||, x = y. 

I get that if A is inhabited, then ||A|| is inhabited by (1). But is it 
true that, if ||A|| is inhabited, then A is inhabited? 

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