Dear all, I formalized my proof of syllepsis in Coq: https://github.com/kristinas/HoTT/blob/kristina-pushoutalg/theories/Colimits/Syllepsis.v I am looking forward to see how it compares to the argument Egbert has been working on. Best, Kristina On 3/8/2021 2:38 PM, Noah Snyder wrote: > The generator of \pi_4(S^3) is the image of the generator of > \pi_3(S^2) under stabilization.  This is just the surjective the part > of Freudenthal.  So to see that this generator has order dividing 2 > one needs exactly two things: the syllepsis, and my follow-up question > about EH giving the generator of \pi_3(S^2).  This is why I asked the > follow-up question. > > Note that putting formalization aside, that EH gives the generator of > \pi_4(S^3) and the syllepsis the proof that it has order 2, are > well-known among mathematicians via framed bordism theory (already > Pontryagin knew these two facts almost a hundred years ago).  So > informally it’s clear to mathematicians that the syllepsis shows this > number is 1 or 2. Formalizing this well-known result remains an > interesting question of course. > > Best, > > Noah > > > On Mon, Mar 8, 2021 at 3:53 AM Egbert Rijke > wrote: > > Dear Noah, > > I don't think that your claim that syllepsis gives a proof that > Brunerie's number is 1 or 2 is accurate. Syllepsis gives you that > a certain element of pi_4(S^3) has order 1 or 2, but it is an > entirely different matter to show that this element generates the > group. There could be many elements of order 2. > > Best wishes, > Egbert > > On Mon, Mar 8, 2021 at 9:44 AM Egbert Rijke > wrote: > > Hi Kristina, > > I've been on it already, because I was in that talk, and while > my formalization isn't yet finished, I do have all the > pseudocode already. > > Best wishes, > Egbert > > On Sun, Mar 7, 2021 at 7:00 PM Noah Snyder > wrote: > > On the subject of formalization and the syllepsis, has it > ever been formalized that Eckman-Hilton gives the > generator of \pi_3(S^2)? That is, we can build a 3-loop > for S^2 by refl_refl_base --> surf \circ surf^{-1} --EH--> > surf^{-1} \circ surf -->  refl_refl_base, and we want to > show that under the equivalence \pi_3(S^2) --> Z > constructed in the book that this 3-loop maps to \pm 1 > (which sign you end up getting will depend on conventions). > > There's another explicit way to construct a generating a > 3-loop on S^2, namely refl_refl_base --> surf \circ surf > \circ \surf^-1 \circ surf^-1 --EH whiskered refl refl--> > surf \circ surf \circ surf^-1 \circ surf^-1 --> > refl_refl_base, where I've suppressed a lot of associators > and other details.  One could also ask whether this > generator is the same as the one in my first paragraph.  > This should be of comparable difficulty to the syllepsis > (perhaps easier), but is another good example of something > that's "easy" with string diagrams but a lot of work to > translate into formalized HoTT. > > Best, > > Noah > > On Fri, Mar 5, 2021 at 1:27 PM Kristina Sojakova > > wrote: > > Dear all, > > Ali told me that apparently the following problem > could be of interest > to some people > (https://www.youtube.com/watch?v=TSCggv_YE7M&t=4350s > ): > > Given two higher paths p, q : 1_x = 1_x, > Eckmann-Hilton gives us a path > EH(p,q) : p @ = q @ p. Show that EH(p,q) @ EH(q,p) = > 1_{p@q=q_p}. > > I just established the above in HoTT and am thinking > of formalizing it, > unless someone already did it. > > Thanks, > > Kristina > > -- > You received this message because you are subscribed > to the Google Groups "Homotopy Type Theory" group. > To unsubscribe from this group and stop receiving > emails from it, send an email to > HomotopyTypeTheory+unsubscribe@googlegroups.com > . > To view this discussion on the web visit > https://groups.google.com/d/msgid/HomotopyTypeTheory/0aa0d354-7588-0516-591f-94ad920e1559%40gmail.com > . > > -- > You received this message because you are subscribed to > the Google Groups "Homotopy Type Theory" group. > To unsubscribe from this group and stop receiving emails > from it, send an email to > HomotopyTypeTheory+unsubscribe@googlegroups.com > . > To view this discussion on the web visit > https://groups.google.com/d/msgid/HomotopyTypeTheory/CAO0tDg7MCVQWLfSf13PvEu%2BUv1mP2A%2BbbNGanKbwHx446g_hYQ%40mail.gmail.com > . > -- You received this message because you are subscribed to the Google Groups "Homotopy Type Theory" group. To unsubscribe from this group and stop receiving emails from it, send an email to HomotopyTypeTheory+unsubscribe@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/HomotopyTypeTheory/7d4b6fd7-3035-e0b9-c966-97dd89d8b457%40gmail.com.