There may be some confusion about univalence and equality of subsets
of a type.
[...]
Now, from a subset A : ℙ X, we get a type A' and an embedding A' → X.(The construction works like this: we have A : X → Prop, and a
projection Prop → U. Then the type A' is the sum (Σ) of composite
function. The embedding is the first projection.)
It is definitely not the case that if A'=B' for A,B : ℙ X then A=B.
[...]
All the misunderstandings in the previous messages are caused bylooking at the particular type X=1 without enough care.
And I think this is what Thomas is pointing out.