From mboxrd@z Thu Jan 1 00:00:00 1970 Date: Fri, 17 Nov 2017 15:53:34 -0800 (PST) From: =?UTF-8?Q?Mart=C3=ADn_H=C3=B6tzel_Escard=C3=B3?= To: Homotopy Type Theory Message-Id: Subject: Yet another characterization of univalence MIME-Version: 1.0 Content-Type: multipart/mixed; boundary="----=_Part_38_1132474227.1510962814547" ------=_Part_38_1132474227.1510962814547 Content-Type: multipart/alternative; boundary="----=_Part_39_131605669.1510962814547" ------=_Part_39_131605669.1510962814547 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 7bit Consider the identity type former Id of the type X:U in the universe U: Id : X -> (X -> U). I've known for some years that this is an embedding of the type X into the type (X->U). This means that the fibers of Id are propositions, or, equivalently, that the maps ap Id : x = y -> Id x = Id y are equivalences for all x,y:X. This depends on univalence. I've just realized that this is actually *equivalent* to univalence. Has anybody noticed this before? Martin ------=_Part_39_131605669.1510962814547 Content-Type: text/html; charset=utf-8 Content-Transfer-Encoding: quoted-printable
Consider the identity type former Id of the type X:U = in the universe U:

=C2=A0 =C2=A0 Id : X -> (X -= > U).

I've known for some years that this is an = embedding of the type X into the type (X->U). This means that the fibers= of Id are propositions, or, equivalently, that the maps ap Id=C2=A0 : x = =3D y -> Id x =3D Id y are equivalences for all x,y:X.

This depends on univalence. I've just realized that this is actually = *equivalent* to univalence. Has anybody noticed this before?

=
Martin

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