Am Sonntag, den 10.01.2016, 11:35 -0500 schrieb Morten Welinder:
> > In that case, you can massively optimize out the whole sort
> > by just counting the number of times each byte appears [...]
> 
> That isn't.  sizeof(char) is guaranteed to be 1.  Is it not, however,
> required to represent bytes.  You could have sizeof(pointer) be
> 1 also and if you so, you really cannot do sorting by counting.

Generally for C it isn't, but for POSIX it is. char there always have
8 bit. So if we are also supposing that pointers have more than 8 bit :)
we never have sizeof(pointer) to be 1. So in that sense we are safe for
musl.

Jens

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