Hello! I've discovered that setuid() deadlocks on a simple stress test (attached: test-setuid.c) that creates threads concurrently with setuid(). (Tested on 1.1.21 on x86_64, kernel 4.15.x and 4.4.x). The gdb output: (gdb) info thr Id Target Id Frame * 1 LWP 23555 "a.out" __synccall (func=func@entry=0x402a7d , ctx=ctx@entry=0x7fffea85b17c) at ../../musl/src/thread/synccall.c:144 2 LWP 23566 "a.out" __syscall () at ../../musl/src/internal/x86_64/syscall.s:13 (gdb) bt #0 __synccall (func=func@entry=0x402a7d , ctx=ctx@entry=0x7fffea85b17c) at ../../musl/src/thread/synccall.c:144 #1 0x0000000000402af9 in __setxid (nr=, id=, eid=, sid=) at ../../musl/src/unistd/setxid.c:33 #2 0x00000000004001c8 in main () (gdb) thr 2 (gdb) bt #0 __syscall () at ../../musl/src/internal/x86_64/syscall.s:13 #1 0x00000000004046b7 in __timedwait_cp (addr=addr@entry=0x7fe99023475c, val=val@entry=-1, clk=clk@entry=0, at=at@entry=0x0, priv=) at ../../musl/src/thread/__timedwait.c:31 #2 0x0000000000404591 in sem_timedwait (sem=sem@entry=0x7fe99023475c, at=at@entry=0x0) at ../../musl/src/thread/sem_timedwait.c:23 #3 0x00000000004044e1 in sem_wait (sem=sem@entry=0x7fe99023475c) at ../../musl/src/thread/sem_wait.c:5 #4 0x00000000004037ae in handler (sig=) at ../../musl/src/thread/synccall.c:43 #5 #6 __clone () at ../../musl/src/thread/x86_64/clone.s:17 #7 0x00000000004028ec in __pthread_create (res=0x7fe990234eb8, attrp=0x606260 , entry=0x400300 , arg=0x0) at ../../musl/src/thread/pthread_create.c:286 #8 0x0000000000400323 in thr () The main thread spins in __synccall with futex() always returning ETIMEDOUT (line 139) and "head" is NULL, while handler() in the second thread is blocked on sem_wait() (line 40). So it looks like handler() updated the linked list, but the main thread doesn't see the update. For some reason __synccall accesses the list without a barrier (line 120), though I don't see why one wouldn't be necessary for correct observability of head->next. However, I'm testing on x86_64, so acquire/release semantics works without barriers. I thought that a possible explanation is that handler() got blocked in a *previous* setuid() call, but we didn't notice its list entry at that time and then overwrote "head" with NULL on the current call to setuid(). This seems to be possible because of the following. 1) There is a "presignalling" phase, where we may send a signal to *any* thread. Moreover, the number of signals we sent may be *more* than the number of threads because some threads may exit while we're in the loop. As a result, SIGSYNCCALL may be pending after this loop. /* Initially send one signal per counted thread. But since we can't * synchronize with thread creation/exit here, there could be too * few signals. This initial signaling is just an optimization, not * part of the logic. */ for (i=libc.threads_minus_1; i; i--) __syscall(SYS_kill, pid, SIGSYNCCALL); 2) __synccall relies on /proc/self/task to get the list of *all* threads. However, since new threads can be created concurrently while we read /proc (if some threads were in pthread_thread() after __block_new_threads check when we set it to 1), I thought that /proc may miss some threads (that's actually why I started the whole exercise in the first place). So, if we miss a thread in (2) but it's created and signalled with a pending SIGSYNCCALL shortly after we exit /proc loop (but before we reset the signal handler), "handler()" will run in that thread concurrently with us, and we may miss its list entry if the timing is right. I've checked that if I remove the "presignalling" loop, the deadlock disappears (at least, I could run the test for several minutes without any problem). Of course, the larger problem remains: if we may miss some threads because of /proc, we may fail to call setuid() syscall in those threads. And that's indeed easily happens in my second test (attached: test-setuid-mismatch.c; expected to be run as a suid binary; note that I tested both with and without "presignalling"). Both tests run on glibc (2.27) without any problem. Would it be possible to fix __synccall in musl? Thanks! (Please CC me on answering, I'm not subscribed to the list). Alexey