From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.org/gmane.linux.lib.musl.general/1717 Path: news.gmane.org!not-for-mail From: Szabolcs Nagy Newsgroups: gmane.linux.lib.musl.general Subject: Re: ldso : dladdr support Date: Fri, 24 Aug 2012 11:38:17 +0200 Message-ID: <20120824093817.GH10731@port70.net> References: <20120817053934.GS27715@brightrain.aerifal.cx> <50311776.9040802@gmail.com> <20120820020626.GD27715@brightrain.aerifal.cx> <503233A8.8000604@gmail.com> <50324A60.7040206@gmail.com> <20120823213937.GS27715@brightrain.aerifal.cx> <20120823222113.GT27715@brightrain.aerifal.cx> <20120824081227.GG10731@port70.net> <503741C7.6070807@gmail.com> Reply-To: musl@lists.openwall.com NNTP-Posting-Host: plane.gmane.org Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii X-Trace: ger.gmane.org 1345801115 22701 80.91.229.3 (24 Aug 2012 09:38:35 GMT) X-Complaints-To: usenet@ger.gmane.org NNTP-Posting-Date: Fri, 24 Aug 2012 09:38:35 +0000 (UTC) To: musl@lists.openwall.com Original-X-From: musl-return-1718-gllmg-musl=m.gmane.org@lists.openwall.com Fri Aug 24 11:38:36 2012 Return-path: Envelope-to: gllmg-musl@plane.gmane.org Original-Received: from mother.openwall.net ([195.42.179.200]) by plane.gmane.org with smtp (Exim 4.69) (envelope-from ) id 1T4qLZ-0002oZ-7Y for gllmg-musl@plane.gmane.org; Fri, 24 Aug 2012 11:38:33 +0200 Original-Received: (qmail 5156 invoked by uid 550); 24 Aug 2012 09:38:29 -0000 Mailing-List: contact musl-help@lists.openwall.com; run by ezmlm Precedence: bulk List-Post: List-Help: List-Unsubscribe: List-Subscribe: Original-Received: (qmail 5147 invoked from network); 24 Aug 2012 09:38:29 -0000 Content-Disposition: inline In-Reply-To: <503741C7.6070807@gmail.com> User-Agent: Mutt/1.5.21 (2010-09-15) Xref: news.gmane.org gmane.linux.lib.musl.general:1717 Archived-At: * musl [2012-08-24 10:56:39 +0200]: > When h1 |= 1 is done the bucket index and first hashval have already been stored in n and hashval. > Then h1 is only used in the (h1 == (h2 | 1)) comparison. > meanwhile i realized that if a%n == b%n and a/2 == b/2 then a == b so there is no loss of information, sorry for the noise